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X plus 7y equals 33 and 3x - 2y equals 7?
x + 7y = 33 (1) --> x = 33 - 7y (1a) 3x - 2y = 7 (2) To solve the simultaneous equations, starts by substituting the value for x found in (1a) into (2): 3(33 - 7y) - 2y = 7 99 - 21y - 2y = 7 -23y = -92 y = 4 Now substitute this value for y into (1a) and solve for x: x = 33 - 7(4) x = 33 - 28 x = 5 Therefore these equations have the solution x = 5, y = 4
What is X plus 7y equals 33 and 3x - 2y equals 7?
x + 7y = 33 multiply through by 3: 3x + 21y = 99 Subtract the second equation from the above equation: 23y = 92 So y = 4 Substituting this value of y in the first equation, x + 28 = 33 ie x = 5 The solution is (x,y) = (5,4)
If x equals 4 and y equals 5 then 9 x plus 7y equals?
x=4 y=5 9x+7y=?? Replace: 9(4)+7(5)= 71
What is 3x plus 7y equals -16 -x-y equals 4?
y = -1 and x = -3
2x plus 6 equals -6 5x plus 7y equals 1?
if: 2x + 6 = -6 then: 2x = -12 x = -6 if: 5x + 7y = 1 then: 5(-6) + 7y = 1 7y = 31 y = 31/7
