if you mean x^2-36
1x^2+0x-36
a=1
b=0
c=-36
you can use quadratic formula
(-b -+ sqrt (b^2-4ac))/2a
you'll get (sqrt(144))/2= 6 and (-sqrt(144))/2= -6 as your two roots
your answer (x+6)(x-6)
or use inspection: what factors of c will give you b when added together if
c=-36 and b=0. the roots 6 and -6 will get you 0 when added and -36 when multiplied.
because 6 and -6 are your chosen factors
the factored expression is (x+6)(x-6)
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The factors of x2-13x+36 are 'x-9' and 'x-4'because the expression (x-9)(x-4) can be simplified as x2-13x+36.
If that's plus 36, it factors to (x - 9)(x - 4)
If it's minus 36, it gets ugly in a hurry.
Factors of 36 which add to 13 are 4 & 9 so:
(x + 4)(x + 9)
or
(x - 4)(x - 9)
depending on the sign of the term 13x.
I'm guessing that's x2 + 13x + 36. So you're looking for two factors of 36 whose sum is 13. It's not 36 and 1, 18 and 2, 12 and 3 or 6 and 6.
(x + 4)(x + 9)
(x + 9)(x + 4)
It can be either or both. 36 is a factor of 72. 36 is a multiple of 9. 36 is both a factor and a multiple of 36.
No, 9 is a factor of 36.
No, 2 is a factor of 36. 36 is a multiple of 2.
36 is both a multiple and a factor of 36.