if you mean x^2-36
1x^2+0x-36
a=1
b=0
c=-36
you can use quadratic formula
(-b -+ sqrt (b^2-4ac))/2a
you'll get (sqrt(144))/2= 6 and (-sqrt(144))/2= -6 as your two roots
your answer (x+6)(x-6)
or use inspection: what factors of c will give you b when added together if
c=-36 and b=0. the roots 6 and -6 will get you 0 when added and -36 when multiplied.
because 6 and -6 are your chosen factors
the factored expression is (x+6)(x-6)
(x + 9)(x + 4)
It can be either or both. 36 is a factor of 72. 36 is a multiple of 9. 36 is both a factor and a multiple of 36.
No, 9 is a factor of 36.
No, 2 is a factor of 36. 36 is a multiple of 2.
36 is both a multiple and a factor of 36.
x2 + 13x + 36 = (x + 9)(x + 4)
(x + 9)(x + 4)
n^2(n + 6)(n^2 - 6n + 36)
x(x2 + 36)
x2 + 36 cannot be factored. You can only factor the difference of two squares, not the sum.
(x + 4)(x + 9)
2(x + 6)(x + 3)
(x-4)
6x3 - 27x2 + 3x + 36 = 3 (x - 4) (x + 1) (2x - 3)
(2x - 3)(x - 12)
(5w-6)2
(x - 6)(5x - 6)