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How do you solve x2-13x plus 36 equals 0 for x?
x2-13x+36=(x-9)(x-4)=0 x=9 or x=4
What binomial is a factor of the trinomial x2-13x 36?
(x - 9)(x - 4)
What are the two factors of the following equation x plus 13x plus 36?
(x+9)(x+4)
Factor this polynomial completely N5 plus 216n2?
n^2(n + 6)(n^2 - 6n + 36)
What is the answer to x squared minus thirteen x plus thirty-six equals zero?
x^2 - 13x + 36 = 0 Factor: (X-9)(X-4) = 0 X = 9 X = 4
Factor x2 plus 13x plus 36 completely?
x2 + 13x + 36 = (x + 9)(x + 4)
Xsquared plus 13x plus 36 Factor completely?
(x + 9)(x + 4)
How do you factor this x2 minus 13x plus 36?
(x-4)
What is the factor of x2 plus 13x plus 36?
(x + 4)(x + 9)
X2 plus 13x plus 36 equals 0?
x2 + 13x + 36 = 0 so (x+4)(x+9) = 0 so that x = -4 or x = -9
How do you solve x2-13x plus 36 equals 0 for x?
x2-13x+36=(x-9)(x-4)=0 x=9 or x=4
What binomial is a factor of the trinomial x2-13x 36?
(x - 9)(x - 4)
Which of the binomials is a factor of this trinomal x2-13x 36?
(x -3)(2x2 + 3x - 4)
What are the two factors of the following equation x plus 13x plus 36?
(x+9)(x+4)
What is x squared plus 13x plus 36 equals 0 factor to?
Well, if that was a - 13X we could factor by inspection, but now the quadratic formula is needed. By inspection the discriminant yields two real roots. X^2 + 13X + 36 = 0 X = - b (+/-) sqrt(b^2-4ac)/2a a = 1 b = 13 c = 36 X = - 13 (+/-) sqrt[b^2 - 4(1)(36)]/2(1) X = - 13 (+/-) sqrt(169 - 144)/2 X = - 13 (+/-) sqrt(25)/2 X = [- 13 (+/-) 5]/2 X = - 4 ------------ X = - 9 -----------
What binomial is a factor of this trinomial x2 - 13x 36?
x-4 is the correct answer for Apex
Factor this polynomial completely N5 plus 216n2?
n^2(n + 6)(n^2 - 6n + 36)
