First take out -3x to make-3x(x2+11)If you're not using imaginary numbers, then you're done. Otherwise factor x2+11 using the sum of two squares rule.-3x(x-sqrt(11)i)(x+sqrt(11)i)
-x(x2 - 2)(x2 + 3)
The GCF is 2xy.
x2-3x+2.25 is the same as 4x2-12x+9 and is (2x-3)(2x-3) when factored
Remove common factors. The common factor is 3x. Then since you must keep the expression constant you put in parentheses what you must multiply 3x by to get each of the original parts of the expression. So the answer must be 3x+3xy=3x(1+y).
x2-3x-28
(x + 1) and (x + 2) are monomial factors of the polynomial x2 + 3x + 2 (x + 1) and (x + 3) are monomial factors of the polynomial x2 + 4x + 3 (x + 1) is a common monomial factor of the polynomials x2 + 3x + 2 and x2 + 4x + 3
x2 + 3x - 40 = (x + 8)(x - 5)
3 - 3x + x2 - x3 = (1 - x)(x2 + 3)
x3 + x2 - 3x - 3 x(x2 + x - 3) - 3
(x2 + 3x + 5)(x2 - 3x + 4)
The GCF is x2
If you mean: x2+3x+2 then it is (x+1)(x+2) when factored
x2-3x-10 = (x+2)(x-5) when factored
28 ( x2, x3 and x4)
If you factor x2 - 3x - 10, you'll get (x-5) (x+2). If your equation is x2 - 3x -10 = 0, then x = 5, and x = -2.
x2 + 3x - 18 = (x + 6)(x - 3)