That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (11 plkus or minus the square root of 14521) divided by 20.
x = 6.575155599650519
x = -5.475155599650519
6x^2 - 11x -10 notice that 6(-10) = -60 which can be factored many ways
1(-60); 2(-30) etc but the important factors are 4(-15)
because 4(-15) = -60 AND 4+(-15) = -11 (coefficent of x)
so rewrite the equation using this fact as 6x^2 + (-15 + 4)x -10
use distrib. prop = 6x^2 -15x +4x -10
group as binomials = (6x^2 - 15x) + (4x - 10)
factor each using GCF = 3x(2x - 5) + 2(2x - 5)
notice the binomials are the same thus the binomial becomes the new GCF
and can be used thus groupind the terms out of the parenthesis to form
= (2x-5)(3x+2) <-- this is the answer
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: 4 plus or minus 2 times the square root of 11x = 10.6332495807108x = -2.6332495807108
Assuming the question is written as: x2+11x-12 This would factor to: (x+12)(x-1)
x(6x - 11)
66x^3 - 36x^2 = 6x^2(11x - 6) 55x - 30 = 5(11x - 6) 66x^3 - 36x^2 + 55x - 30 = (6x^2 + 5)(11x - 6)
It is not possible to be certain about it being the "greatest" common factor, because 2 or 3 or 6 may be a factor of x, but the general solution for practical purposes is: 11x = 11*x and -66 = 11*(-1)*2*3 so [g]cf is 11.
(2x - 1)(5x + 8)
(x - 1)(2x - 9)
The factors are -1(2x + 1)(3x + 4)
Factor out -2: -2(x squared +11x-20). This is fully factored.
x^3 - 121x
No answer in integers, nor outside the realm of imaginary numbers. Typo?
3x2 - 11x - 4 = (x-4)(3 x + 1)
-x-6-(-11x) + (-1) Remove the brackets: -x-6+11x-1 Collect and simplify like terms: 10x-7 A - - is equal to a +
21
You have to experiment with different factors of 2, and different factors of 15. In this case, 2x2 - 11x + 15 = (2x - 5) (x - 3)
11x = 10x-19 Subtact 10x fromboth sides:- x = -19
-11x-1 = -10x-8 -11x+10 = -8+1 -1x = -7 x = 7