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That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (11 plkus or minus the square root of 14521) divided by 20.
x = 6.575155599650519
x = -5.475155599650519
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Taiga6x^2 - 11x -10 notice that 6(-10) = -60 which can be factored many ways
1(-60); 2(-30) etc but the important factors are 4(-15)
because 4(-15) = -60 AND 4+(-15) = -11 (coefficent of x)
so rewrite the equation using this fact as 6x^2 + (-15 + 4)x -10
use distrib. prop = 6x^2 -15x +4x -10
group as binomials = (6x^2 - 15x) + (4x - 10)
factor each using GCF = 3x(2x - 5) + 2(2x - 5)
notice the binomials are the same thus the binomial becomes the new GCF
and can be used thus groupind the terms out of the parenthesis to form
= (2x-5)(3x+2) <-- this is the answer
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How do you factor W2-8W-28?
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: 4 plus or minus 2 times the square root of 11x = 10.6332495807108x = -2.6332495807108
Factor x2 plus 11x-12?
Assuming the question is written as: x2+11x-12 This would factor to: (x+12)(x-1)
Factor 6 x2 - 11x?
x(6x - 11)
Factor the polynomial by grouping the terms together two at a time 66x3 - 36x2 plus 55x - 30?
66x^3 - 36x^2 = 6x^2(11x - 6) 55x - 30 = 5(11x - 6) 66x^3 - 36x^2 + 55x - 30 = (6x^2 + 5)(11x - 6)
The gcf of 11x and -66?
It is not possible to be certain about it being the "greatest" common factor, because 2 or 3 or 6 may be a factor of x, but the general solution for practical purposes is: 11x = 11*x and -66 = 11*(-1)*2*3 so [g]cf is 11.
