That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (11 plkus or minus the square root of 14521) divided by 20.
x = 6.575155599650519
x = -5.475155599650519
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: 4 plus or minus 2 times the square root of 11x = 10.6332495807108x = -2.6332495807108
Assuming the question is written as: x2+11x-12 This would factor to: (x+12)(x-1)
x(6x - 11)
The factors of (11x) are (1), (11), (x), and (11x). For (55), the factors are (1), (5), (11), and (55). Both expressions share the common factors (1), (11), and their respective constants. Thus, (11) is a common factor of both (11x) and (55).
66x^3 - 36x^2 = 6x^2(11x - 6) 55x - 30 = 5(11x - 6) 66x^3 - 36x^2 + 55x - 30 = (6x^2 + 5)(11x - 6)
(2x - 1)(5x + 8)
(x - 1)(2x - 9)
The factors are -1(2x + 1)(3x + 4)
Factor out -2: -2(x squared +11x-20). This is fully factored.
x^3 - 121x
No answer in integers, nor outside the realm of imaginary numbers. Typo?
3x2 - 11x - 4 = (x-4)(3 x + 1)
-x-6-(-11x) + (-1) Remove the brackets: -x-6+11x-1 Collect and simplify like terms: 10x-7 A - - is equal to a +
21
You have to experiment with different factors of 2, and different factors of 15. In this case, 2x2 - 11x + 15 = (2x - 5) (x - 3)
11x = 10x-19 Subtact 10x fromboth sides:- x = -19
To determine what must be added to (11x + 2y) to produce (10x - 4y), we can set up the equation: [ 11x + 2y + k = 10x - 4y ] Subtracting (11x + 2y) from both sides gives: [ k = 10x - 4y - 11x - 2y = -x - 6y ] Thus, (-x - 6y) must be added to (11x + 2y) to produce (10x - 4y).