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Factor x2 plus 11x-12?
Assuming the question is written as: x2+11x-12 This would factor to: (x+12)(x-1)
Factor the polynomial by grouping the terms together two at a time 66x3 - 36x2 plus 55x - 30?
66x^3 - 36x^2 = 6x^2(11x - 6) 55x - 30 = 5(11x - 6) 66x^3 - 36x^2 + 55x - 30 = (6x^2 + 5)(11x - 6)
What is the factor of x3-216?
(x - 6)(x2 + 6x + 36)
How do you factor out x2 plus 11x plus 30?
That doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: (-11 plus or minus the square root of -31) divided by 4.x = -2.75 + 1.3919410907075054ix = -2.75 - 1.3919410907075054iwhere i is the square root of negative one.
How do you factor 36-x2?
Setting to zero may help. 36 - X2 = 0 36 = X2 take square root each side (+/-) 6 = X ========
Factor the polynomial x2-11x-12?
x2 -11x-12= (x-12)(x+1)
Factor x2 plus 11x-12?
Assuming the question is written as: x2+11x-12 This would factor to: (x+12)(x-1)
How do you factor x squared - 11x equals -10?
21
What is the factor of x2-5x-66?
x2-5x-66 x2-11x+6x-66 x(x-11)+6(x-11) (x+6)(x-11)
How do you factor x2 plus 11x plus 30?
The factors of (x2 + 11x + 30) are (X + 5) and (x + 6)You want to look for two numbers, when multiplied equal 30, and when added equal 11. Start with factors of 30, and see what they add to: 5+6=11, and 5*6=30.
How do you factor x2-11x-10?
It doesn't factor evenly if it were x**2-11x+10: x**2-11x+10 = (x-1)(x-10)
Factor x2 11x 24?
Not possible to be specific since you have not provided the sign of the term in x, but there are two possible factorisations; (x + 3)(x + 8) = x2 + 11x + 24 and (x - 3)(x - 8) = x2 - 11x + 24
X2 plus 11x plus 6 rational zeros?
x^2 + 11x + 6 has no rational zeros.
What is the factor of x2 squared minus11x plus 24?
x2 - 11x + 24 = (x - 3)(x - 8)
What Are the roots of x2 plus 11x plus 30 equals 0?
x2 + 11x + 30 = 0 (x + 5)(x + 6) = 0 so the roots are -5 and -6
How do you do x2 equals 11x -10?
To solve for x: x2 = 11x - 10 x2 - 11x = -10 x2 - 11x + 10 =0 (x - 1)(x - 10) = 0 x = {1, 10)
How do you factor x2 11x 10?
Can you improve the question? It's hard to tell what you mean.
