2x + x
(x + x) + x
x + x + x = 3x
2x + x = 3x
* * * * *
No, no, no! The correct answer is:
x2 + x = x(x + 1).
It is sometimes best to test answers with various substitution values.
x2 + x = 3x, only when x = 0 or 2; but not otherwise.
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(2x + 1) is as much as you can factor it without resorting to fractions. If you want to get x by itself,
2*(x + 1/2)
Use the quadratic formula as there are no integer roots.
x2 + 3x + 2 factors as (x + 1)(x + 2) and x2 - 3x + 2 factors as (x - 1)(x - 2)
Short answer: No common factors and no real roots.
Long answer: It can be factored, it just won't be pretty. Any time you're getting into the cube root of -1, it's dangerous territory.
Unless you know the value of X, the only factors of (x+2) that you can identify are itself and one (1)
(x + 2)(x - 1)
x2 + 5x + not really sure what that extra plus is for... this is the most you can factor it... x(x + 5)
x - 4x + 4 = -3x + 4 which cannot be factorised.
-x(x2 - 2)(x2 + 3)
Take out the common factor, 3: 3x + 6 = 3(x + 2).