answersLogoWhite

0

(x - 2)(x - 1)

User Avatar

Wiki User

12y ago

What else can I help you with?

Related Questions

What is the quadratic equation used for?

It is used to solve quadratic equations that cannot be factored. Usually you would factor a quadratic equation, identify the critical values and solve, but when you cannot factor you utilize the quadratic equation.


Can Quadratic equations that can be solved using the quadratic formula also be solved by factoring?

Yes, however not all quadratic equations can easily be solved by factoring, sometimes you can factor and sometimes it is easier to use the quadratic formula. Example: x2 + 4x + 4 This can be easily factored to (x + 2)(x +2) Therefore the answer is -2 by setting x +2 = 0 and solving for x This can be done using the quadratic equation and you would get the same results, however, it was much faster to factor instead.


What is the factor quadratic of 18x2 plus 15x plus 2?

18x2 + 15x + 2 = (3x + 2)(6x + 1)


How do you factor -5b2 plus 7b-2?

It is: (-5b+2)(b-1) with the help of the quadratic equation formula


Can a factor pair have an extra addition problem?

Yes and they do in factoring quadratic equations.Yes and they do in factoring quadratic equations.Yes and they do in factoring quadratic equations.Yes and they do in factoring quadratic equations.


How do you solve a quadratic equation that will not factor?

How you solve an equation that doesn't factor is to plug a quadratic equation's format; ax2+bx+c into the quadratic formula which is x=-b+square root to (b2-4ac)/2a.


What is the quadratic trinomials factor of 12xsquared-20x -8?

12x2-20x-8 = (12x+4)(x-2)


How do you solve 4x2 - 4x plus 2 equals 0?

If you can't factor it easily, use the quadratic formula.


What method(s) would you choose to solve the quadratic equation -2x2 8x 130?

I'd substitute the values -2, 8 and 130 into the quadratic formula and wind up with two real solutions: 2 plus or minus -1 times the square root of 69 x = -6.306623862918075 x = 10.306623862918075


How do you solve Quadratic functions?

All you do is set the quadratic function to equal to 0. Then you can either factor or use the quadratic formula to solve for your unknown variable.


How do you compute the intercepts of a quadratic function?

Use the quadratic equation. If ax+bx+c=0 x=(-b±(b^2-4ac)^(1/2))/2a. You could also complete the square, factor,or graph the equation.


What is the factor of 2x2-10x plus 3?

Doesn't factor evenly, use quadratic