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That doesn't factor neatly. Applying the quadratic equation, we find two real solutions: -2 plus or minus 2 times the square root of 3

x = 1.4641
x = -5.4641

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βˆ™ 11y ago
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βˆ™ 12y ago

2(x3 - x - 4)

If that were 2x2, the answer would be 2(x - 2)(x + 1)

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βˆ™ 9y ago

That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: 2 plus or minus the square root of 6.

x = 4.4494897427831779

x = -0.4494897427831779

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βˆ™ 14y ago

Assuming the equation equates to 0.

X2 - 4 = 0

X2 = 4

X * X = 4

X = 2.

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βˆ™ 9y ago

(x + 2)(x - 2)

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βˆ™ 9y ago

(x^2 + 1)(x^2 - 2)

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Q: How do you factor x2 plus 4x - 8?
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