That doesn't factor neatly. Applying the quadratic equation, we find two real solutions: -2 plus or minus 2 times the square root of 3
x = 1.4641
x = -5.4641
2(x3 - x - 4)
If that were 2x2, the answer would be 2(x - 2)(x + 1)
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: 2 plus or minus the square root of 6.
x = 4.4494897427831779
x = -0.4494897427831779
Assuming the equation equates to 0.
X2 - 4 = 0
X2 = 4
X * X = 4
X = 2.
(x + 2)(x - 2)
(x^2 + 1)(x^2 - 2)
(x + 3)(4x + 5)
(x + 4)(x + 8)
4x2 + 12 = 4(x2 + 3)4x^2 + 8x + 3x + 6 = 4x(x + 2) + 3(x + 2)
When factored: (x+4)(x-8)
if that's +32, it factors to -(x - 4)(x + 8)
x2 + 4x - 96 = (x - 8)(x + 12).
x2+4x-32 = (x-4)(x+8) when factored
(x + 12)(x - 8)
4x2+4x-8 4(x2+x-2) and (4x+8)(x-1)
x2 - 4x - 32 = (x - 8)(x + 4)
4x+8
(x - 4) or (x + 8)
x2 + 4x - 32 = (x + 8)*(x - 4)
x3 - 2x2 - 4x + 8 = (x2 - 4)(x - 2) = (x + 2)(x - 2)(x - 2)
(x + 3)(4x + 5)
If that's +4x, the answer is (x - 4)(x + 8) If that's -4x, the answer is (x + 4)(x - 8)
Y = X2 - 4X + 12 set to 0 X2 - 4X + 12 = 0 subtract 12 from each side X2 - 4X = - 12 now, take the linear term ( - 4 ), halve it, square it and add it to both sides X2 - 4X + 4 = - 12 + 4 factor the left side, gather terms on the right (X - 2)2 = - 8 add 8 to each side (X - 2)2 + 8 = 0 ------------------------ (2, 8) ------------the vertex of this function