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If that's + 2y, the answer is (y + 4)(y - 2)

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12y ago
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12y ago

I feel like there is something wrong with your question because subtracting y2 on both sides leaves you with 8y=0; then, y=0

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12y ago

8y2-10y-3

8y2-12y+2y-3

4y(2y-3)+1(2y-3)

(4y+1)(2y-3)

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Wiki User

14y ago

4(2y-3)

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Q: How do you factor y2 2y-8?
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