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If that were z^2 - 16z + 64, it would factor very neatly to (z - 8)(z - 8) or (z - 8)^2
As it is, you could use z(z^2 - 16) + 64 or the much more cumbersome
-1/27 (3 z+2 2^(2/3) (3 (9-sqrt(69)))^(1/3)+4 3^(2/3) (2/(9-sqrt(69)))^(1/3)) (-9 z^2+(12 3^(2/3) (2/(9-sqrt(69)))^(1/3)+6 2^(2/3) (3 (9-sqrt(69)))^(1/3)) z-8 2^(1/3) (3 (9-sqrt(69)))^(2/3)-48 3^(1/3) (2/(9-sqrt(69)))^(2/3)+48)
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Factor the following expression ax plus ay minus AZ?
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Their product.
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To raise to a power it's a lot clearer if you use ^ on a PC. For example, x^2 for x squared. I think you want to factorise 4x^2 - 25(y^2)(z^2). We recognise this as a difference of squares: (2x)^2 - (5yz)^2 and so it factorises as (2x - 5yz)(2x + 5yz).
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(c - z)(c^2 + cz + z^2)
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How do you type z squared?
z^2
Factor the following expression ax plus ay minus AZ?
ax + ay - AZ = a(x + y - z)
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4z squared (z+4) (z+4)
What was the formula for Pythagoras famous theorem?
x squared + y squared = z squared.
Z squared equals 4z plus 21?
(z=-3) and (z=7)
