Steps for factoring trinomials:
Example
20x**3-62x**2-28x
1. Factor out GCF from each term
20x**3-62x**2-28x - 2x(10x**2-31x-14)
2. Multiply First and Last term
10*-14=140
3. Find 2 factors of Step 2 (140) whose sum is the second term (-31)
140=2*2*5*7
-140=-2*70, 2*-70
-140=-5*28, 5*-28
-140=-7*20, 7*-20
-140=-4*35, 4*-35
-140=-10*14, 10*-14
4. Rewrite
2x(10x**2-31x-14) = 2x(10x**2+4x-35x-14)
5. Factor pairs of terms
2x(10x**2+4x-35x-14) = 2x(2x(5x+2)-7(5x+2))
6. Factor
2x(2x(5x+2)-7(5x+2)) = 2x((2x-7)(5x+2))
2x(2x-7)(5x+2)
Special cases
A. ax**2-b, where sqrt(a) and sqrt(b) are both whole numbers
ax**2-b = (sqrt(a)x+sqrt(b))(sqrt(a)x-sqrt(b))
4x**2-81 =(2x-9)(2x+9)
B. x**2+ax+b where b=c*d and a=c+d
x**2+ax+b = (x+c)(x+d)
x**2-8x-105
Factors of 105:
105=3*5*7
-105=-3*35, 3*-35
-105=-5*21, 5*-21
-105=-7*15, 7*-15
x**2-8x-105 = (x+7)(x+-15)
C. x**2+ax+b where b=c**2 and a=2c
x**2+ax+b = (x+c)**2
x**2+8x+16 = (x+4)**2
NOTES:
> b=c*d OR b=-c*-d
> -b=-c*d OR -b=c*-d
Factors
Factor it once, and then factor the factors.
In algebra, the factor theorem is a theorem linking factors and zeros of a polynomial. It is a special case of the polynomial remainder theorem.The factor theorem states that a polynomial has a factor if and only if
True
You need to know whether the given factor is x + 5 or x - 5. Then it is a simple problem in long division.
Factors
B
a
a
graph!
Graph factor
graph apex xD
false
I suppose you mean factoring the polynomial. You can check by multiplying the factors - the result should be the original polynomial.
It is useful to know the linear factors of a polynomial because they give you the zeros of the polynomial. If (x-c) is one of the linear factors of a polynomial, then p(c)=0. Here the notation p(x) is used to denoted a polynomial function at p(c) means the value of that function when evaluated at c. Conversely, if d is a zero of the polynomial, then (x-d) is a factor.
Completely Factored
2 or 5