To find the prime factors of a number, divide the number by the smallest Prime number as many times as needed, then by the next smallest prime, forming a "factor tree."
180 / 2 = 90
90 / 2 = 45
45 / 3 = 15
15 / 3 = 5
The prime factors are 2 x 2 x 3 x 3 x 5 or 22 x 32 x 5
No. The Prime Factors of 180 are: 2, 3, 5.
As a product of its prime factors: 2*2*3*3*5 = 180
2 x 2 x 3 x 3 x 5 = 180
The prime factors of 50 are: 2 and 5
it is easier to find the prime factorization because you do not have to keep multiplying over and over and over again!!!!
To work out the prime factors of 180 in index form, you first need to find the prime factors of 180. Start by dividing 180 by the smallest prime number, which is 2. Continue dividing by prime numbers until you cannot divide any further. The prime factors of 180 are 2, 2, 3, 3, and 5. In index form, this would be written as 2^2 * 3^2 * 5.
No. The Prime Factors of 180 are: 2, 3, 5.
The prime factors are: 2,3,5
The prime factors of 180 are 2, 3, and 5 .
As a product of its prime factors: 2*2*3*3*5 = 180
2,3,5
prime factors of 180:(180) = 2 * (90)(90) = 2 * (45)(45) = 3 * (15)(15) = 3 * 5prime factors of 180 are: 2*2*3*3*5
Since they don't share any prime factors, multiply them. The LCM is 180.
As a product of its prime factors in exponents: 22*32*5 = 180 So 5 is its largest prime factor.
2, 3 and 5
2, 3 and 5
As a product of its prime factors: 2*2*3*3*5 = 180