That factors to 2(x + 4)(x + 6) x = -4, -6
If that's +28, the answer is (x - 4)
2(x - 6)(x + 6)
2x2-x-15 = 0 When factorised: (2x+5)(x-3) = 0
The factorisation is as follows: 2x2 + 7x - 9 = (x - 1)(2x + 9).
To solve for x: 2x2 + 10 = 58 2x2 = 48 x2 = 24 x = √24 x = √4 × √6 x = 2√6
If that's + 2x2, the answer is x(x + 3)(x - 1) x = 0, -3, 1 If that's - 2x2, the answer is x(x - 3)(x + 1) x = 0, 3, -1
2x2-x-3 = 0= 4 - x - 3 = 0= 1 - x = 0= 1 = xTherefore x = 1
Solve by factoring.2x2 - 3x + 1 = 0
2x2+1x-3=0 4+x-3=0 x+1+0 x=-1 is your final answer
2x2 - 9x = 18 2x2 - 9x -18 = 0 (2x - 18)(x + 9) x= -9 and 9
4x2 - 2x - 12= 2x2 - x - 6= 2x2 - 4x + 3x - 6= 2x(x - 2) + 3(x - 2)= (x - 2)(2x + 3)
2x2 = 8x x = 8x/2x x = 4 Check: 2(4)2 = 8(4) 2(16) = 32 32 = 32
2x2 - 5x + 6 = ?x = -1(2 x (-1)2) - (5 x -1) + 6 = ?(2 x 1) - (-5) + 6 = ?2 + 5 + 6 = 13
2x2-12x-54 = 0 Solve by factoring or using the quadratic equation formula or by completing the square: (2x+6)(x-9) = 0 Therefore: x = -3 or x = 9
By using the quadratic equation formula: x = -5 and x = 3
2x2 = x2 - 2 Subtract x2 from both sides: x2 = -2 Take square roots: x = + or - i*sqrt(2) where i is the imaginary sqrt of -1.