The polynomial 7x3 + 6x2 - 2 has a degree of 3, making it cubic.
The degree is the highest power of the variable. For example, x5 + 3x3 - x + 4 is of degree 5, since the highest power of "x" is 5.
Yes, f(x) = 2 is a polynomial of degree 0 (because there are no x terms).
Yes. If the coefficient of the third degree terms in one polynomial are the additive inverses (minus numbers) of the coefficient of the corresponding terms in the second polynomial. Eg: 3x3 + 2x2 + 5 and -3x3 + x - 7 add to give 2x2 + x - 2
Yes. If and only if the coefficients of x4 are of the same magnitude and opposite sign.
The polynomial 7x3 + 6x2 - 2 has a degree of 3, making it cubic.
the answer is 21 3 x 7 = 21
7X^3 Third degree polynomial.
210 7x3=21x10=210
That completely depends on the value of 'x'.
x(7x ^2 - 4x + 8)
The four solution values of x of 3x4 + 7x3 + 4x2 = 0 are: x = -11/3, -1, 0 (repeated) 3x4 + 7x3 + 4x2 = 0 ⇒ x2(3x2 + 7x + 4) = 0 ⇒ x2(3x + 4)(x + 1) = 0 ⇒ x2 = 0 → x = 0 (repeated) or (3x + 4) = 0 → x = -4/3 = -11/3 or (x + 1) = 0 → x = -1
2x4 - 7x3 + x2 + 7x - 3 = (x + 1)(2x3 - 9x2 + 10x - 3) = (x + 1)(x - 1)(2x2 -7x + 3) = (x + 1)(x - 1)(x - 3)(2x -1)
5 + 6x² + 3x - 7x³ + x6 would have the degree of 6.
7x3 is equal to 21.
For the equation: x5+7x3-30x=0 The highest exponent in the entire equation is 5 (from x5), so the equation is of degree 5.
(x + 3)(7x^2 + 1)