3r + 12 = 3*(r+4)
Wiki User
∙ 2009-12-01 11:56:0615(3r - 4s + 1)
There are no rational factors.
(x - 2)(x + 12)
6(x + 2)
(r + 1)(3r - 5)
If that's 3r + 12, that factors to 3(r + 4)
3r + 3r + 2t = 6r + 2t
-5 = 7 + 3r | subtract 7 -12 = 3r | divide by 3 -4 = r
5
3r-r equals 12 = -9
(3r + 18)/12 = (4r - 48)/4Multiply both sides by 12: (3r + 18) = 3*(4r - 48)or: 3r + 18 = 12r - 144Subtract 3r from both sides: 18 = 9r - 144Add 144 to both sides: 162 = 9rDivide both sides by 9: 18 = rAnswer: r = 18
(3r - 2)(3r - 2) or (3r - 2) squared.
No, it's simply 3r, because multiplication (r multiplied by 3) comes first in the order of operations.
-7p + 5r - 6p + 3r = -7p - 6p + 5r + 3r = -(7 + 6)p + (5 + 3)r = -13p + 8r
(3r + 2)(r - 5)
If: -5 = 7+3r then the value of r works out as -4
-2r(3r - 11)(3r + 11)