x2 - y2 = 16
then (x + y)*(x - y) = 16
This has an infinite number of solutions lying on the hyperbola.
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x2-81=(x-9)(x+9) Factors: x-9, x+9
5x2 + 9x + 13 has no real factors.
I'm presuming its factors for a monic quadratic trinomial--of form : X squared + BX + C . You need the numbers that MULTIPLY to give C and ADD up to give B Eg X squared + 8X + 12 factors to ( X+2) (X + 6 ) BUT X squared + 7X + 12 factors to (X +3 )(X + 4) Hope this helps. Phil.
7(x + 3)(x - 3)
(x - 5)(x - 3)