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How do you factor x-y plus xy-1?
(x-y) + (xy - 1) = (x - 1)(y + 1)
Factor xy plus 2x plus 4y plus 8?
xy plus 2x plus 4y plus 8 or (xy+2x) + (4y+8) or x(y+2) + 4(y+2) or (x+4)(y+2)
Is x plus y equivalent to y plus x?
yes, it's the same, the answer will still be xy.
The sum of two number is 10 and their product is 30 the sum of their reciprocals is?
Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3
If the sum of two numbers is 12 and the product is 24 What is the sum of the reciprocals?
1/x+1/y y/xy+x/xy x+y/xy=12/24 12/24=1/2 1/2 is the answer.
How do you factor xy x squared y?
If that's xy + x^2y, it factors to xy(x + 1) If it's something else, please re-submit your question with any plus signs written out.
How do you factor x-y plus xy-1?
(x-y) + (xy - 1) = (x - 1)(y + 1)
Factor 2 plus 2y plus x plus xy?
2+2y+x+xy=(x+2)(y+1)
How xy plus x plus y plus 1 will solve?
xy + x + y + 1 is an expression, not an equation. An expression cannot be solved.
Factor 2x squared plus 2x plus xy plus y?
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X plus XY equals 8 solve for Y?
x+xy=8 xy=-x+8 y=-1+8/x
What is the answer to xy-x plus 2y-2?
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What is 2 over X plus 1 over Y simplified they are fractions?
I understand you want [(2/x) + (1/y)] as a single fraction. The common denominator is (xy): 2/x = (2y)/(xy); and 1/y = x/(xy), so the answer is (2y + x) / (xy)
What is the inverse of y(2-x plus 3) plus 1?
The multiplicative inverse of 5y -xy + 1 is 1/5y -xy + 1 The additive inverse of 5y - xy + 1 is -5y + xy - 1
Are the factors of x2 are x and x plus 1?
The factors of x2 are x and x x times x plus 1 = x2 + x
Factoring this expression Check by multiplying factors xy plus ay plus ab plus bx?
xy + ay + ab + bx = y(x + a) + b(a + x) = y(x + a) + b(x + a) = y(x + a) + b(x + a) = (y + b)(x + a) To check, multiply out the two brackets making sure that each pair is evaluated.
How do you solve for x when y equals quantity x plus 2 divided by quantity x plus 10?
y=(x+2)/(x+10) xy+10y=x+2 xy-x=2-10y x(y-1)=2-10y x=(2-10y)/(y-1)
