They are x = 0, -5 and +8.
If the coefficients of a polynomial of degree three are real it MUST have a real zero. In the following, asymptotic values are assumed as being attained for brevity: If the coeeff of x3 is positive, the value of the polynomial goes from minus infinity to plus infinity as x goes from minus infinity to plus infinity. The reverse is true if the coefficient of x3 is negative. Since all polynomials are continuous functions, the polynomial must cross the x axis at some point. That's your root.
The degree of this polynomial is 2.
here is a list of numbers starting from million to vigintillion 1 plus 6 zeros is 1 million 1 plus 9 zeros is 1 billion 1 plus 12 zeros is 1 trillion 1 plus 15 zeros is 1 quadrillion 1 plus 18 zeros is 1 quintillion 1 plus 21 zeros is 1 sextillion 1 plus 24 zeros is 1 septillion 1 plus 27 zeros is 1 octillion 1 plus 30 zeros is 1 nonillion 1 plus 33 zeros is 1 decillion 1 plus 36 zeros is 1 undecillion 1 plus 39 zeros is 1 duodecillion 1 plus 42 zeros is 1 tredecillion 1 plus 45 zeros is 1 quattuordecillion 1 plus 48 zeros is 1 quindecillion 1 plus 51 zeros is 1 sexdecillion 1 plus 54 zeros is 1 septendecillion 1 plus 57 zeros is 1 octodecillion 1 plus 60 zeros is 1 novemdecillion 1 plus 63 zeros is 1 vigintillion
yes, and it is 14x
It is 6.
An algebraic function is a function built from polynomial and combined with +,*,-,/ signs. The transcendental it is not built from polynomial like X the power of Pie plus 1. this function is transcendental because the power pi is not integer number in result it can't be a polynomial.
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (-1 plus or minus the square root of 265) divided by 12 x = 1.2732350496749756 x = -1.439901716341642
It is f(x) = -x2 or (-x)2, whichever you intended.
A fifth degree polynomial.
The actual equation itself is the polynomial. There is no polynomial for it, and your question doesn't really make sense.
It is a quadratic polynomial.
It is 9x + 2.
7X^3 Third degree polynomial.
what kind of polynomial is shown 3x3+x+1
If the coefficients of a polynomial of degree three are real it MUST have a real zero. In the following, asymptotic values are assumed as being attained for brevity: If the coeeff of x3 is positive, the value of the polynomial goes from minus infinity to plus infinity as x goes from minus infinity to plus infinity. The reverse is true if the coefficient of x3 is negative. Since all polynomials are continuous functions, the polynomial must cross the x axis at some point. That's your root.
The degree of this polynomial is 2.
Both - a polynomial expression, if you like.