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3 Factor the given polynomial completely Choose the correct factors from those given belowx2 4x-12 a. x 2 b. x 6 c. x-2 d. x 4 e. x-4 f. x-6?
x^2 + 4x - 12 factors to (x + 6)(x - 2) The correct answers are b and c
What are the ratings and certificates for The Big C - 2010 Crossing the Line 2-13?
The Big C - 2010 Crossing the Line 2-13 is rated/received certificates of: Argentina:16 Netherlands:6
How would you solve x - 8x plus 12 equals 0?
Method 1:Completing the Squarex2 - 12x + 16 = 0x2 - 12x + 16 + 20 = 0 + 20x2 - 12x + 36 = 20(x - 6)2 = 20√((x - 6)2) = ±√(20)√((x - 6)2) = ±√(2*2*5)x - 6 = ±2√(5)x - 6 + 6 = 6 ±2√(5)x - 6 + 6 = 6 ±2√(5)x = 6 ± 2√(5)Method 2:Quadratic FormulaStandard form of a quadratic equation:ax2 + bx + c = 0x2 - 12x + 16 = 0a = 1b = -12c = 16Quadratic Formulax = (-b ± √(b2 - 4ac))/ 2ax = (-(-12) ± √((-12)2 - 4(1)(16)))/ 2(1)x = ((12) ± √(144 - 64))/ 2x = (12 ± √(80))/ 2x = (12 ± 4√(5))/ 2x = 12/2 ± (4/2)√(5)x = 6 ± 2√(5)
Asquare plus b square plus c square -ab -bc -ca equals 0 then show that a equals b equals c?
a^2 + b^2 + c^2 - ab - bc - ca = 0=> 2a^2 + 2b^2 + 2c^2 - 2ab - 2bc - 2ca = 0 => a^2 - 2ab + b^2 + b^2 - 2bc + c^2 + c^2 - 2ca + a^2 = 0 => (a - b)^2 + (b - c)^2 + (c - a)^2 = 0 Each term on the left hand side is a square and so it is non-negative. Since their sum is zero, each term must be zero. Therefore: a - b = 0 => a = b b - c = 0 => b = c.
What is the relationship between carbon-12 carbon-13 and carbon-14?
They all have 6 protons. C-12 has 6 neutrons, c-13 has 7 neutrons and C-14 has 8neutrons.
