There is a formula for factoring the "difference of squares." In this case, the answer is
(9 - 4x)(9 + 4x)
9 x 9 = 81 9 squared = 81 3 squared times 3 squared = 81
x2-81=(x-9)(x+9) Factors: x-9, x+9
9 squared is 81. Two digits lower than 81 is 79. 79 is a prime number. Its only factors are one and itself. That does not compute. 78 has 26 and 6 as factors. 78 is three digits lower than 81. That does not compute.
16, 81, 625 and so on. Prime numbers to the 4th power.
Square numbers like 1, 4, 9, 16, 25, 36, 49, 64, 81, 100
81 x 2 - 16 = 146
4x2/81 = 1 - 16x2/25100x2 = 25*81 - 16*81x21396x2 = 2025x2 = 2025/1396x = +/- 1.2044, approx.
9 squared is 81 and 16 squared is 256
x2-81 = (x-9)(x+9)
9x2 - 6xy + y2 - 81 = (3x - y)2 - 92 = (3x - y - 9)(3x - y + 9)
78 minus78
79, -79
(9 - 5u)(9 + 5u)
9x2 - 6xy + y2 - 81 = (3x - y)2 - 81 = (3x - y - 9)*(3x - y + 9)
The answer? There is no "answer" There cannot be an answer because they are all different. In order to make calculations, the variables have to be the same. x squared, xy, y squared are the variables, and none of them match. Therefore your "answer" must look like this: 9x squared - 6xy + y squared - 81. Hope I Helped :D
81
I believe it is prime as you have written it. change the end to + 81 and it factors as (2x - 1)(x-9)(x+9)