x2-81=(x-9)(x+9)
Factors: x-9, x+9
That doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: -2 plus or minus i times the square root of 17.x = -2 + 4.123105625617661ix = -2 - 4.123105625617661iwhere i is the square root of negative one.
That doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: (1 plus or minus the square root of -191) divided by 24t = 0.0416666 repeating + 0.5758447900452189it = 0.0416666 repeating - 0.5758447900452189iwhere i is the square root of negative one.
That doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: -3 plus or minus i, where i is the square root of negative 1.
x2 - 2x - 14 doesn't factor neatly. Applying the quadratic formula, we find two real solutions: 1 plus or minus the square root of 15x = 4.872983346207417x = -2.872983346207417
3.14 times the radius SQUARED.
Find factors of -99 which sum to -2. Solution appears to be 9 and -11 (x + 9)(x - 11)
The prime factors of a squared number are the prime factors, if any, of its square root.
Find factors of -5 that can be added to make -4, in this case -5 and 1, so: (x - 5)(x + 1) = x2 - 4x - 5
B squared equals c squared minus a squared then to find B take the square root of you answer for b squared
You try to find two factors of -58 whose sum is -27 .You find that -29 and +2 will do it, so . . .x2 - 27x - 58 = (x - 29) (x + 2)
It can be found by: hypotenuse squared minus known side squared = unknown side squared
The formula for finding the angles is called " Pythagorean Thyrum " It states that a squred plus b squared equals c squared so therefore c squared minus a squared will equal b squared. i hope that helps
there has to be more to the question is there a way you can tell what the equation equals
Subtract the squared longer leg's squared length from the hypotenuse's square to obtain the squared shorter leg length. Then find the square root of that answer for your final answer. In other words: 53 squared minus 45 squared equals your squared answer.
a triangle has 3 sides. the longest side is always C. the other 2 are A and B (which one is which doesn't matter). u can find side C using A squared plus B squared equals C squared. It's basically AxA + BxB =CxC. to find side A, use C squared minus B squared. CxC - BxB = AxA . To find B, use the same equation to find A except switch B with A. CxC - AxA = BxB.-Mathnerd157
That doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: 1 plus or minus i where i is the square root of negative one.
x2 - 3 doesn't factor neatly. Applying the quadratic formula, we find two real solutions: Zero plus or minus the square root of three.x = 1.7320508075688772x = -1.7320508075688772