4x2 + 8x + 4 = 4 (x2 + 2x + 1) = 4 (x + 1)2
Take out the common factor, 3: 3x + 6 = 3(x + 2).
(x + 4)(x + 1)
(x + 2)(x - 1)
x2+6x-7 = (x+7)(x-1) when factored
I take it LCM is the lowest common multiple For the above the only common multiple is 1 you get x=1 1^2 + (8*1) -9 = 0 and 1^2 -1 = 0 Hope this helps
(-4,-1)
x2+8x = -3x2+5 4x2+8x-5 = 0 (2x+5)(2x-1) = 0 x = -5/2 or x = 1/2
4x2 + 8x + 4 = 4 (x2 + 2x + 1) = 4 (x + 1)2
(x + 9)(x - 1)
(x2 + 14 + 48 / (x + 8) = (x2 + 62) / (x + 8) =(x2 + 8x - 8x - 64 + 126) / (x + 8) = x - 1 + 126/(x+8)
4x2 + 8x + 4 = 4 (x2 + 2x + 1) = 4 (x + 1)2
x2 + 8x - 9 = 0(x + 9) (x - 1) = 0(x + 9) = 0 . . . . . x = -9(x - 1) = 0 . . . . . x = 1
(x+ 7)(x + 1) so x = -1 or -7
(x + 9)(x - 1)
When factored it is: (x+9)(x-1)
x2 - 8x = 1 ∴ x2 - 8x + 16 = 17 ∴ (x - 4)2 = 17 ∴ x - 4 = ±√17 ∴ x = 4 ± √17