The GCF is 8.
To determine if (8a) is a factor of 60, we need to check if 60 can be evenly divided by (8a). Since 60 is not divisible by 8 (as (60 \div 8 = 7.5)), (8a) cannot be a factor of 60 for any value of (a) other than zero. Therefore, (8a) is not a factor of 60.
4b2-16 =4(b2-4) =4(b+2)(b-2)
32a + 8= 8(4a+1)
The GCF of 16 24 and 48 is 8.Factors of 16: 1, 2, 4, 8, and 16Factors of 24: 1, 2, 3, 4, 6, 8, 12, and 24Factors of 48: 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48Common factors of 16, 24, and 48: 1, 2, 4, and 8A simpler process is by the method of prime factorization:The prime factors of these numbers are16 = 2 x 2 x 2 x 224 = 2 x 2 x 2 x 348 = 2 x 2 x 2 x 2 x 3Their common factors are 2 x 2 x 2 = 8The GCF is 8.
To solve the expression (8a \cdot 3 - 12.2), first multiply (8a) by (3) to get (24a). Then, subtract (12.2) from (24a). The final expression is (24a - 12.2).
The GCF of 6a^2 and 8a is 2a.
The GCF is 4a^2
8a + 1 is in its simplest form and does not factor.
Since 8 is a factor of 16, it is automatically the GCF. That factors to 8(a - 2)
24
To determine if (8a) is a factor of 60, we need to check if 60 can be evenly divided by (8a). Since 60 is not divisible by 8 (as (60 \div 8 = 7.5)), (8a) cannot be a factor of 60 for any value of (a) other than zero. Therefore, (8a) is not a factor of 60.
8a(5a2-1)
the graph of y=a2 + 8a + 16 is
24
8A + (8A+8) + (8A+16) = 888 24A + 24 = 888 ===> 24A = 864 ===> A = 36 The multiples are 8A, 8A+8, 8A+16 = 288, 296, 304. Sum = 888.
(2a + 1)(2a - 5)
8a(x - 7)