A, B and C aren't numbers, they're letters. Probably variables. Without knowing what numbers they represent, we can't calculate their LCM.
The greatest common multiple of any set of integers is infinite.
The greatest factors of A, B, and C, respectively, are the absolute values of A, B, and C. The greatest common factor of A, B, and C is 1.
LCM(8, C, A) = 8*C*A.
The following code for example is a solution (you could do it with less variables, but this is more readable):int GCD(int a, int b){int n, k, c;n = (a>b)?a:b;k = (a>b)?b:a;while (k){c = n%k;n=k;k=c;}return n;}
b 108
The greatest common multiple of any set of integers is infinite.
L= lowest C= common M= multiple Example: The lowest common multiple of 5 and 2 is:..... (list the factors) 5= 5, 10, 15, 20, 25 2= 2, 4, 6, 8, 10 The lowest common multiple would be 10, since it appears on both of the sequences, AND its is the LOWEST number.
lcm(a,b,c,d) = lcm(lcm(a,b,c),d) = lcm(lcm(a,b),lcm(c,d))
A + B is also a multiple of C. ------------------------------------------- let k, m and n be integers. Then: A = nC as A is a multiple of C B = mC as B is a multiple of C → A + B = nC + mC = (n + m)C = kC where k = n + m kC is a multiple of C. Thus A + B is a multiple of C.
It is b: 80
If A and B are multiples of C, then A + B is also a multiple of C: If A is a multiple of C then A = mC for some integer m If B is a multiple of C, then B = nC for some integer n → A + B = mC + nC = (m + n)C = kC where k = m + n and is an integer → A + B is a multiple of C
C is this your homework??
a). The least common multiple of 4 and 6 is 12 . b). The least common multiple of 3 and 8 is 24 . c). The least common multiple of 2 and 12 is 12 . d). The least common multiple of 3 and 6 is 6 . Gosh, I guess they all have.
There are none because there is no such thing as a Greatest Common Multiple (GCM). If {a, b, c, ... x} is any set of integers, then a*b*c*...*x is a common multiple. Then twice that number is also a common multiple and is greater. And then, twice THAT number is a common multiple and greater still. It is easy to show that this process can go on for ever and so there is no such thing as a GCM.
To answer that, you'll need to have a numerical value for the letters.
To calculate the least common multiple (lcm) of decimals (integers) and fractions you first need to calculate the greatest common divisor (gcd) of two integers: int gcd (int a, int b) { int c; while (a != 0) { c = a; a = b % a; b = c; } return b; } With this function in place, we can calculate the lcm of two integers: int lcm (int a, int b) { return a / gcd (a, b) * b; } And with this function in place we can calculate the lcm of two fractions (a/b and c/d): int lcm_fraction (int a, int b, int c, int d) { return lcm (a, c) / gcd (b, d); }
Class A is Lowest Efficiency