1003
Any multiple of 360 between 1080 and 9720 inclusive.
28, 56, 84 you can always find a common multiple of two numbers by multiplying them (but that won't always be the least common multiple)... the other common multiples can b found by multiplying that number with any other positive integer... for example, if you have two numbers (a and b), then one of their common multiples is a x b (but not always the smallest one), and the others are 2 x a x b, or any other positive integer times a x b
If it's to be divisible by 5, it must end in 5 or 0. And if it's to be divisible by 3, adding the digits together must result in a multiple of 3.While some numbers that end in zero will still work, you can guarantee that the number won't be divisible by four by choosing a number that ends in five.So you'd need a four-digit number, that ends in 5, whose digits add up to a multiple of 3. The smallest such number would be 1005, and the largest would be 9975.(However, the actual largest number that would fit your question is 9990; remember that I did say some numbers that end in zero would still work.)
There are more than four, starting with 12, 15, 18 and 21.
Every number is divisible by 21. Any element of the set of numbers of the form 21*k where k is an integer is evenly divisible.
1002
This depends on what you mean by smallest. The smallest four-digit whole number is 1,000; the smallest four-digit real number is .0001 (1/10,000); the smallest four-digit integer is -9,999.
The smallest positive integer with four different digits is 1023. This number uses the smallest digits available (1, 0, 2, and 3) while ensuring that the first digit is not zero, thus maintaining its status as a positive integer.
The smallest four digit odd integer is 1001.
Provided that the first digit cannot be 0, 1000 is the smallest number with four digits. Otherwise there are smaller numbers with 0 to thousandth digit such as 0100, 0050. The smallest integer in such instance is 0000.
That would be the same as the smallest four-digit even number: 1,000, which also happens to be the smallest four-digit whole number.
To find a four-digit number divisible by both 23 and 9, we first determine the least common multiple (LCM) of the two numbers. The LCM of 23 and 9 is 207. The smallest four-digit number is 1000, and the largest is 9999. Dividing 1000 by 207 gives approximately 4.83, so the smallest four-digit number that is a multiple of 207 is 5 × 207 = 1035.
If you allow non integers, then your smallest four-digit number would be .0001. If you only allow integers, then your smallest four-digit number would be 1000. Your largest four-digit number would be 9999.
The smallest four digit number is 1000. It is even so 1001 is the smallest four digit number that is odd.
A four-digit number that is divisible by 2, 5, and 9 must be divisible by their least common multiple, which is 90. The smallest four-digit number is 1000, and the largest is 9999. The smallest four-digit number divisible by 90 is 1080, while the largest is 9990. Therefore, any four-digit number like 1080 or 9990 can serve as an example.
The smallest four-digit number in which no digit is repeated is 1023. It starts with the smallest digit (1) to ensure it's a four-digit number, followed by the next smallest digits (0, 2, and 3) without any repetitions.
The smallest four-digit number not using zero is 1000. In a four-digit number, the first digit cannot be zero, so the smallest possible value for the first digit is 1. The remaining three digits can be any number from 0-9, so the smallest possible four-digit number is 1000.