Multiples of 30 from 120 to 990
A normal die has two multiples of 3: 3 and 6.
there aren't any as otherwise they wouldn't be prime numbers
What are the first three common multiples of four and five
The first 3 multiples of 4 are: 4, 8, and 12.The first 3 multiples of 9 are: 9, 18, and 27.
60 numbers
30, 60 and 90.
There are none.
45 multiples of 2 plus 30 multiples of 3 minus 15 multiples of 6 equals 60 numbers
The prime factors of 81 are 3, 3, 3, and 3 - so the only two-digit factor is 27, which is 3 x 3 x 3.
100, 110 and 120 are 3 digit multiplies of 10.
6134
To determine the number of 3-digit numbers that are multiples of 5, we need to find the first and last 3-digit multiples of 5. The first 3-digit multiple of 5 is 100, and the last 3-digit multiple of 5 is 995. To find the total number of such multiples, we can use the formula (Last - First) / 5 + 1 = (995 - 100) / 5 + 1 = 180. Therefore, there are 180 3-digit numbers that are multiples of 5.
Any multiple of four must be even; any number ending in three is odd. Look at the multiples of four from 1 to 9. They are in the order : 4,8,12,16,20,24,28,32,36. Now, any number when multiplied by 4, will have the one's digit as the one's digit of the above multiples In the above multiples, no multiple has 3 as the one's digit, i.e., no multiple ends in three. Take an example. 15x4 will have 0 in the one's digit because 5x4 = 20 and has 0 in the one's place.
Multiples of 30 from 120 to 990
lcm(2, 3, 5) = 30 → 2 digit common multiples are 30, 60, 90.
They are: one, two, three, four!