The largest two-digit multiple of six is 96.
1, 3, 9, 11, 33, 99.
1, 2, 5, 10, 25, 50 1, 3, 9, 11, 33, 99
There are three:99 = 1 x 9999 = 3 x 3399 = 9 x 11
The factors of 33 are: 1, 3, 11, and 33.The prime factors of 33 are: 3 and 11.The factors of 99 are: 1, 3, 9, 11, 33, and 99.The prime factors of 99 are: 3 and 11.
99. 9 divided by 9=1
1
99 x 9 = 891.
The answer depends on what the tens digit is greater than, and what the ones digit does then.
The digit of 115 in the tens place is the 1.
Since the greatest digit is 9 and the greatest 2-digit number is 99, the product of them is 891.
69
The 1 is in the tens place.
So far, you know that your number has a seven in the tens column:7?The ones digit is one more than the tens digit, which is 7.7+1=8Your number is 78.
The units digit of a two digit number exceeds twice the tens digit by 1. Find the number if the sum of its digits is 10.
how does 100 meet the specification? 1 is in the hundreds digit and 0 is in the tens digit. 1 is not at least 0. this is a confusing question?!
1