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We won't be able to answer this accurately without knowing the polynomials.

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13y ago

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What is the Best Describes The Relationship Between (x - 2) And The Polynomial 2x3 plus X2 - 3?

To determine the relationship between ( (x - 2) ) and the polynomial ( 2x^3 + x^2 - 3 ), we can perform polynomial division. If ( (x - 2) ) divides the polynomial evenly, then ( (x - 2) ) is a factor of the polynomial. Alternatively, we can evaluate the polynomial at ( x = 2 ); if the result is zero, it confirms that ( (x - 2) ) is a factor. In this case, substituting ( x = 2 ) gives ( 2(2)^3 + (2)^2 - 3 = 16 + 4 - 3 = 17 ), indicating that ( (x - 2) ) is not a factor of the polynomial.


Factor the polynomial x2 - 5x plus 6 Write each factor as a polynomial in descending order?

(x-2)(x-3)


Factor the following polynomial. x2 - 4?

(x-2)(x+2)


Factor the polynomial x2 5x - 24 Enter each factor as a polynomial in descending order?

x^2 + 5x - 24 = (x - 3)(x + 8)


If a polynomial is divided by (x - a) and the remainder equals zero then (x - a) is a factor of the polynomial.?

Yes, that's correct. According to the Factor Theorem, if a polynomial ( P(x) ) is divided by ( (x - a) ) and the remainder is zero, then ( (x - a) ) is indeed a factor of the polynomial. This means that ( P(a) = 0 ), indicating that ( a ) is a root of the polynomial. Thus, the polynomial can be expressed as ( P(x) = (x - a)Q(x) ) for some polynomial ( Q(x) ).


What is the polynomial factor theorem?

Suppose p(x) is a polynomial in x. Then p(a) = 0 if and only if (x-a) is a factor of p(x).


what is the factor the polynomial 2x2-12x-80?

2(x + 4)(x - 10)


Factor polynomial x2 plus 2x-8?

(x+4)(x-2)


What best describes the relationship between x plus 1 and the polynomial x2 minus x minus 2?

X2 - X - 2(X + 1)(X - 2)===============(X + 1) is a factor of the above polynomial.


The polynomial x - 2 is a factor of the polynomial Fx equals 5x2 - 6x plus 4?

False


What are the zeros of the polynomial function f(x)x3-2x2-8x?

To find the zeros of the polynomial function ( f(x) = x^3 - 2x^2 - 8x ), we first factor the expression. We can factor out ( x ) from the polynomial, giving us ( f(x) = x(x^2 - 2x - 8) ). Next, we can factor the quadratic ( x^2 - 2x - 8 ) into ( (x - 4)(x + 2) ), leading to ( f(x) = x(x - 4)(x + 2) ). Therefore, the zeros of the function are ( x = 0 ), ( x = 4 ), and ( x = -2 ).


Factor the polynomial x3-2x2 plus x-2?

x3 - 2x2 + x - 2 =(x - 2)(x2 + 1)