We won't be able to answer this accurately without knowing the polynomials.
Yes, if there is no remainder after division, the divisor is a factor.
(x + 11y)(x - 12y)
This polynomial doesn't factor. The only thing you can do is take out parts of some terms, e.g. 2(2x3 + 10x2 + x) - 3.
Yes, f(x) = 2 is a polynomial of degree 0 (because there are no x terms).
Take out the common factor, 3: 3x + 6 = 3(x + 2).
To determine the relationship between ( (x - 2) ) and the polynomial ( 2x^3 + x^2 - 3 ), we can perform polynomial division. If ( (x - 2) ) divides the polynomial evenly, then ( (x - 2) ) is a factor of the polynomial. Alternatively, we can evaluate the polynomial at ( x = 2 ); if the result is zero, it confirms that ( (x - 2) ) is a factor. In this case, substituting ( x = 2 ) gives ( 2(2)^3 + (2)^2 - 3 = 16 + 4 - 3 = 17 ), indicating that ( (x - 2) ) is not a factor of the polynomial.
(x-2)(x-3)
(x-2)(x+2)
x^2 + 5x - 24 = (x - 3)(x + 8)
Yes, that's correct. According to the Factor Theorem, if a polynomial ( P(x) ) is divided by ( (x - a) ) and the remainder is zero, then ( (x - a) ) is indeed a factor of the polynomial. This means that ( P(a) = 0 ), indicating that ( a ) is a root of the polynomial. Thus, the polynomial can be expressed as ( P(x) = (x - a)Q(x) ) for some polynomial ( Q(x) ).
Suppose p(x) is a polynomial in x. Then p(a) = 0 if and only if (x-a) is a factor of p(x).
2(x + 4)(x - 10)
(x+4)(x-2)
X2 - X - 2(X + 1)(X - 2)===============(X + 1) is a factor of the above polynomial.
False
To find the zeros of the polynomial function ( f(x) = x^3 - 2x^2 - 8x ), we first factor the expression. We can factor out ( x ) from the polynomial, giving us ( f(x) = x(x^2 - 2x - 8) ). Next, we can factor the quadratic ( x^2 - 2x - 8 ) into ( (x - 4)(x + 2) ), leading to ( f(x) = x(x - 4)(x + 2) ). Therefore, the zeros of the function are ( x = 0 ), ( x = 4 ), and ( x = -2 ).
x3 - 2x2 + x - 2 =(x - 2)(x2 + 1)