Yes, if there is no remainder after division, the divisor is a factor.
(x + 11y)(x - 12y)
This polynomial doesn't factor. The only thing you can do is take out parts of some terms, e.g. 2(2x3 + 10x2 + x) - 3.
Yes, f(x) = 2 is a polynomial of degree 0 (because there are no x terms).
Take out the common factor, 3: 3x + 6 = 3(x + 2).
(x-2)(x-3)
(x-2)(x+2)
x^2 + 5x - 24 = (x - 3)(x + 8)
Suppose p(x) is a polynomial in x. Then p(a) = 0 if and only if (x-a) is a factor of p(x).
(x+4)(x-2)
2(x + 4)(x - 10)
X2 - X - 2(X + 1)(X - 2)===============(X + 1) is a factor of the above polynomial.
False
x3 - 2x2 + x - 2 =(x - 2)(x2 + 1)
(x + 2)(x - 7)
(x + 1)(x + 2)
If you mean: x2+3x+2 then it is (x+1)(x+2) when factored