How do you find distance when given initial velocity final velocity and acceleration?

Answer 1

Here are the velocity equations D= (vi+vf/2)t

D=vit + 1/2 at^2

V^2=Vi^2 + 2ad

V= vi+at

a= (vf-vo)/t According to your question, use V^2=Vi^2 + 2ad v= Final velocity

vi= initial velocity

a= acceleration

d= displacement

Answer 2

Assuming you start from rest (0) and accelerate uniformly.

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acceleration = distance / (0.5 * time2), then having found acceleration:

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final velocity = acceleration * time

Answer 3

First note the following formulaes

Velocity= Distance/Time.............................................1

Acceleration= Change in velocity/Time..........................2

Therefore say if V2 and V1 is given the difference between them is the change in velocity if not then consider the value of speed as change in velocity

Now find the Time from second equation = V(speed)/A(accel)..............3

Make eq 1 as Distance =Velocity*Time

Since you have the value of velocity and Time substitute and get the value of Distance travelled

Please note that the referred problem is independent of mass

Answer 4

As we responded last time you posted the same question:

You should use the formula you learned for just exactly this situation.

V = V0 + a t

Final speed = (initial speed) + (acceleration) x (time)

Answer 5

D=vt+1/2(at^2)
Where
D=Distance
v=Initial Velocity
a=Acceleration
t=Time
Except we do not know the time t. Use v2 = u2 - 2aD. u is final velocity.

Answer 6

Distance = |(v2 - u2)/(2a)|

where

initial velocity = u

final velocity = v

accelaration = s

Answer 7

You should use the formula you learned for just exactly this situation.

V = V0 + a t

Final speed = (initial speed) + (acceleration) x (time)

Answer 8

By using the formula in physics

Answer 9

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Answer 10

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