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vf2 = vi2 +ad, where vf is the final velocity, vi is the initial velocity, a is acceleration, and d is displacement. In physics, velocity is the change in position of an object over a given time interval, and change in position is displacement, rather than distance.

To find displacement, manipulate the equation in the following manner. Assume vi is zero.

vf2 = 0 + 2ad

vf2 = 2ad

vf2/2a = 2ad/2a

vf2/2a = d

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12y ago
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4mo ago

To find the distance using final velocity and minimum acceleration, you can use the formula: distance = (final velocity)^2 / (2 * acceleration). Simply square the final velocity, then divide by 2 times the minimum acceleration to get the distance traveled.

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Q: How do you find distance with final velocity and minimum acceleration?
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If an object is accelerating what equation relates the distance traveled by that object to the initial velocity final velocity and time?

The equation that relates the distance traveled by a constantly accelerating object to its initial velocity, final velocity, and time is the equation of motion: [ \text{distance} = \frac{1}{2} \times (\text{initial velocity} + \text{final velocity}) \times \text{time} ] This equation assumes constant acceleration.


How do you find the distance given only the initial velocity traveled time and final velocity?

You can use the equation: distance = (initial velocity + final velocity) / 2 * time. This formula assumes constant acceleration.


To find the acceleration of an object moving in a straight line you must calculate the charge in distance during unit of time?

To find the acceleration of an object moving in a straight line, you must calculate the change in velocity during a unit of time. Acceleration is the rate of change of velocity over time, not distance. It is given by the formula acceleration = (final velocity - initial velocity) / time.


How do you find displacement when you only have acceleration initial velocity and final velocity?

You can use the equation: Displacement = (final velocity squared - initial velocity squared) / (2 * acceleration). Plug in the values of final velocity, initial velocity, and acceleration to calculate the displacement.


How do you find distance with uniform velocity time final velocity and initial velocity?

If the velocity is uniform, then the final velocity and the initial velocity are the same. Perhaps you meant to say uniform acceleration. In any event, the question needs to be stated more precisely.

Related questions

How do you calculate acceleration from velocity?

There are 3 formula 1. Final velocity = starting velocity + (acceleration)(time) 2. Final velocity^2 = starting velocity^2 + 2(acceleration)(distance) 3. Distance = (starting velocity)(time) + 1/2(acceleration)(time^2) Use whichever you can use.


How do you find the distance if only the final velocity and the acceleration is given?

You can find the distance using the equation: distance = (final velocity)^2 / (2 * acceleration). Square the final velocity, divide it by twice the acceleration to get the distance traveled before coming to a stop.


How do you calculate acceleration from distance and time?

Acceleration= Distance/time (distance divided by time) That's the dumbest answer I've ever heard.. Acceleration = Final Velocity - Initial Velocity/Time Velocity = Displacement/Time So you can't calculate acceleration from distance and time, you can only do velocity.


If a car goes in 6.8 seconds how do you figure out the acceleration?

To calculate acceleration, you need to know the initial velocity of the car and its final velocity after 6.8 seconds. The acceleration can be found using the formula: acceleration = (final velocity - initial velocity) / time.


How do you find a final velocity without distance but given time?

Without distance, you have to know time, initial velocity, and acceleration, in order to find final velocity.


How do you calculate acceleration when given velocity and distance?

v2 - u2 = 2as so that a = (v2 - u2)/2s where u = initial velocity v = final velocity s = distance a = acceleration


What is the equation for change in acceleration?

The equation for change in acceleration is Δa = a_end - a_start, where Δa is the change in acceleration, a_end is the final acceleration, and a_start is the initial acceleration.


If an object is accelerating what equation relates the distance traveled by that object to the initial velocity final velocity and time?

The equation that relates the distance traveled by a constantly accelerating object to its initial velocity, final velocity, and time is the equation of motion: [ \text{distance} = \frac{1}{2} \times (\text{initial velocity} + \text{final velocity}) \times \text{time} ] This equation assumes constant acceleration.


If you know the acceleration of a car its initial velocity the time interval what can you predict?

Its final velocity, the distance covered.


When calculating acceleration to find the change in velocity you subtract the what velocity from the final velocity?

When calculating acceleration to find the change in velocity, you subtract the initial velocity from the final velocity. The formula for acceleration is: acceleration = (final velocity - initial velocity) / time.


Is it true that to calculate acceleraltion you need to know both the final and the initial velocity of an object?

No. That's only one of several possibilities. -- with initial velocity, distance, and time, you can calculate acceleration -- with final velocity, distance, and time, you can calculate acceleration -- with force and mass, you can calculate acceleration -- with initial and final momentum, you can calculate acceleration -- with initial and final kinetic energy, you can calculate acceleration -- with mass, velocity at either end, and kinetic energy at the other end, you can calculate acceleration And I'm sure there are several more that I've missed.


How do you find the distance given only the initial velocity traveled time and final velocity?

You can use the equation: distance = (initial velocity + final velocity) / 2 * time. This formula assumes constant acceleration.