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vf2 = vi2 +ad, where vf is the final velocity, vi is the initial velocity, a is acceleration, and d is displacement. In physics, velocity is the change in position of an object over a given time interval, and change in position is displacement, rather than distance.
To find displacement, manipulate the equation in the following manner. Assume vi is zero.
vf2 = 0 + 2ad
vf2 = 2ad
vf2/2a = 2ad/2a
vf2/2a = d
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If an object is accelerating what equation relates the distance traveled by that object to the initial velocity final velocity and time?
The equation that relates the distance traveled by a constantly accelerating object to its initial velocity, final velocity, and time is the equation of motion: [ \text{distance} = \frac{1}{2} \times (\text{initial velocity} + \text{final velocity}) \times \text{time} ] This equation assumes constant acceleration.
How do you find the distance given only the initial velocity traveled time and final velocity?
You can use the equation: distance = (initial velocity + final velocity) / 2 * time. This formula assumes constant acceleration.
To find the acceleration of an object moving in a straight line you must calculate the charge in distance during unit of time?
To find the acceleration of an object moving in a straight line, you must calculate the change in velocity during a unit of time. Acceleration is the rate of change of velocity over time, not distance. It is given by the formula acceleration = (final velocity - initial velocity) / time.
How do you find displacement when you only have acceleration initial velocity and final velocity?
You can use the equation: Displacement = (final velocity squared - initial velocity squared) / (2 * acceleration). Plug in the values of final velocity, initial velocity, and acceleration to calculate the displacement.
How do you find distance with uniform velocity time final velocity and initial velocity?
If the velocity is uniform, then the final velocity and the initial velocity are the same. Perhaps you meant to say uniform acceleration. In any event, the question needs to be stated more precisely.
