Amps x volts = watts
So, assuming you are running on 110 volt line, the answer is 65 watts/110 volts=.591 amps.
The amps drawn by a 65 watt light bulb should be 65/120 or 0.54167. This fraction of an ampere may be restated as 541.67 milli-amps.
Each 32-watt bulb in a 48-inch fluorescent light typically draws around 0.27 amps. Therefore, a two-bulb setup would draw approximately 0.54 amps in total.
A 65 Watt incandescent light bulb should draw 65W/120V = 541.67mA
To calculate the amperage of a 40-watt bulb, you need to use the formula: Amps = Watts / Volts. If the bulb operates at 120 volts (standard for US households), the amperage will be 0.33 amps (40 watts / 120 volts).
1 amp
The amps drawn by a 65 watt light bulb should be 65/120 or 0.54167. This fraction of an ampere may be restated as 541.67 milli-amps.
A 60 watt light bulb typically draws 0.5 amps from a 120-volt power source. This is calculated by dividing the wattage (60 watts) by the voltage (120 volts).
Each 32-watt bulb in a 48-inch fluorescent light typically draws around 0.27 amps. Therefore, a two-bulb setup would draw approximately 0.54 amps in total.
A 65 Watt incandescent light bulb should draw 65W/120V = 541.67mA
A 120 volt table lamp with a 75 watt bulb will pull 0.625 amps. With a 100 watt bulb it will pull 0.833 amps. And with a modern fluorescent 13 watt bulb it will pull 0.108 amps.
Watts = Volts X Amps. Amps=Watt / Volts. So, with a 240V mains, a 60W bulb draws 0.25amps. On a 12 system (car/auto) a 60W bulb draws 5 amps. On a 110V mains, a 60W bulb draws .55 Amps.
A 60 watt bulb at 12 volts will pull 5 amps of current.
To find the current in amps for a 50-watt light bulb, you can use the formula ( I = \frac{P}{V} ), where ( I ) is the current in amps, ( P ) is the power in watts, and ( V ) is the voltage in volts. For example, if the bulb operates at 120 volts, the current would be ( \frac{50}{120} ), which equals approximately 0.42 amps. If the bulb operates at a different voltage, simply adjust the voltage in the formula accordingly.
To calculate the amperage of a 40-watt bulb, you need to use the formula: Amps = Watts / Volts. If the bulb operates at 120 volts (standard for US households), the amperage will be 0.33 amps (40 watts / 120 volts).
It is drawing .06 amps.
Watts = Volts x Amps x Power Factor. An incandescent light bulb is a resistive load so PF = 1. ANSWER: = 1/2 Amp
Thomas Edison invented the vacuum sealed filiment light bulb. James Watt coined the term "watt" as the work done by an electrical circuit, which can be calculated as Volts multiplied by Amps.