To calculate the amperage, you can use the formula: Amps = Watts/Volts. For a 65-watt light bulb at 120 volts, the amperage would be 0.54 amps.
Each 32-watt bulb in a 48-inch fluorescent light typically draws around 0.27 amps. Therefore, a two-bulb setup would draw approximately 0.54 amps in total.
A 65-watt light bulb operating at 120 volts draws approximately 0.54 amps of current. You can calculate this by dividing the wattage (65 watts) by the voltage (120 volts) to get the amperage.
To calculate the amperage of a 40-watt bulb, you need to use the formula: Amps = Watts / Volts. If the bulb operates at 120 volts (standard for US households), the amperage will be 0.33 amps (40 watts / 120 volts).
1 amp
To calculate the amperage, you can use the formula: Amps = Watts/Volts. For a 65-watt light bulb at 120 volts, the amperage would be 0.54 amps.
A 60 watt light bulb typically draws 0.5 amps from a 120-volt power source. This is calculated by dividing the wattage (60 watts) by the voltage (120 volts).
Each 32-watt bulb in a 48-inch fluorescent light typically draws around 0.27 amps. Therefore, a two-bulb setup would draw approximately 0.54 amps in total.
A 65-watt light bulb operating at 120 volts draws approximately 0.54 amps of current. You can calculate this by dividing the wattage (65 watts) by the voltage (120 volts) to get the amperage.
A 120 volt table lamp with a 75 watt bulb will pull 0.625 amps. With a 100 watt bulb it will pull 0.833 amps. And with a modern fluorescent 13 watt bulb it will pull 0.108 amps.
Watts = Volts X Amps. Amps=Watt / Volts. So, with a 240V mains, a 60W bulb draws 0.25amps. On a 12 system (car/auto) a 60W bulb draws 5 amps. On a 110V mains, a 60W bulb draws .55 Amps.
A 60 watt bulb at 12 volts will pull 5 amps of current.
To calculate the amperage of a 40-watt bulb, you need to use the formula: Amps = Watts / Volts. If the bulb operates at 120 volts (standard for US households), the amperage will be 0.33 amps (40 watts / 120 volts).
It is drawing .06 amps.
Watts = Volts x Amps x Power Factor. An incandescent light bulb is a resistive load so PF = 1. ANSWER: = 1/2 Amp
Thomas Edison invented the vacuum sealed filiment light bulb. James Watt coined the term "watt" as the work done by an electrical circuit, which can be calculated as Volts multiplied by Amps.
To calculate the resistance of a 40 watt bulb, you need to know the voltage it operates at. You can use the formula P = V^2 / R, where P is power (40 watts) and V is voltage. Without voltage information, the resistance cannot be determined.