Wiki User
∙ 11y agoFor an approximate calculation:
specific heat capacity for water = 4.18 J/(g*degC)
(how much energy is required per gram per change in degrees C)
mass = 25g
Change in temperature = 60-10 = 50 degC
energy required = mass * change in temperature * specific heat capacity
= 25g * 50 degC * 4.18 J/(g*degC)
Wiki User
∙ 11y agoThe specific heat capacity of water is 4.18 J/g°C. The heat required can be calculated using the formula: Q = m x c x ∆T, where Q is the heat energy, m is the mass of water, c is the specific heat capacity of water, and ∆T is the change in temperature. Plugging in the values, we get: Q = 25 g x 4.18 J/g°C x (60°C - 10°C) = 4180 J. So, 4180 Joules of heat are required.
Wiki User
∙ 14y agoSpecific Heat capacity( S) is the amount of heat required to raise the temperature of unit mass of substance through 10C.
Let H be heat supplied, T be temperature change, m be mass of body.
Now as per our definition
Specific Heat capacity = heat supplied/mass of body*temperature change
or S = H/T*m
Putting values into the formula we have:
S = 26kJ/250g*1670C
S = 26000J/(1/4 kg * 1670C)
S = 622.75 J/kg* 0C
Hence Specific Heat capacity of substance = 622.75 J/kg* 0C.
This is done by assuming no phase change occurs during heating and substance remained in the same state as on beginning.
Wiki User
∙ 11y agoUsing the equation Q=MC theta 600J= 0.25*C*3 600J= 0.75*C 600J/.75=C 600J*1/4=C C=15J/Kg centigrade
kalimoon02
Wiki User
∙ 11y ago2.22 J/g°C
To bring the ice block to 0 degrees Celsius, you would need 150,000 Joules (Q = mcΔT). To melt the ice at 0 degrees Celsius, you would need 3,375,000 Joules (Q = mLf). Heating the water from 0 to 100 degrees Celsius would require 1,500,000 Joules (Q = mcΔT). Turning the water to steam at 100 degrees Celsius would need 10,500,000 Joules (Q = mLv). Finally, heating the steam to 120 degrees Celsius would require 600,000 Joules (Q = mcΔT). In total, you would need 15,125,000 Joules of heat energy.
To convert 50 kg of water at 80 degrees Celsius to steam at 100 degrees Celsius, you need to calculate the heat energy needed to raise the temperature of water from 80 to 100 degrees Celsius (specific heat capacity of water) and then the heat energy needed for water to steam phase change (latent heat of vaporization of water). The total heat energy required can be calculated using the formula: Q = mcΔT + mL, where Q is the heat energy, m is the mass, c is the specific heat capacity, ΔT is the temperature change, and L is the latent heat of vaporization.
To convert 2.35 kilojoules of heat to degrees Celsius, you need to know the specific heat capacity of the substance being heated. Once you have this value, you can use the formula: Heat energy (in joules) = mass * specific heat capacity * change in temperature. By rearranging the formula, you can calculate the change in temperature in degrees Celsius.
The specific heat capacity of water is 4.18 J/g°C, which means it takes 4.18 Joules of energy to raise 1 gram of water by 1 degree Celsius. To raise the temperature of 8.1 g of water by 20 degrees Celsius, you would need 8.1 g * 20°C * 4.18 J/g°C = 676.56 Joules of energy.
The specific heat of solid uranium is approximately 0.116 joules/gram degrees Celsius. It is a measure of the amount of heat required to raise the temperature of a unit mass of the substance by one degree Celsius.
The answer is 53,683 kJ.
No, heat is not measured in degrees Celsius. Heat is a form of energy and is typically measured in joules or calories. Temperature, on the other hand, is measured in degrees Celsius.
8.200 J
False. Heat is measured in units of energy such as calories or joules, not in degrees Celsius. Temperature, on the other hand, is measured in degrees Celsius.
Heat energy is typically measured in joules (J) or calories (cal). Degrees Celsius and degrees Fahrenheit are units of temperature, not energy.
Approx 4974 Joules.
The specific heat capacity of water is 4.18 Joules/gram degrees Celsius. Therefore, it would take 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
The amount of energy required to raise the temperature of 1 kg of water by 1 degree Celsius is approximately 4,186 Joules. Therefore, to raise the temperature by 2 degrees Celsius, you would need about 8,372 Joules of energy.
To raise the temperature of a substance, you need to calculate the heat energy using the specific heat capacity of the substance. Without knowing the specific heat capacity of the substance in question, it's not possible to determine the exact amount of energy required to raise the temperature from 30 to 45 degrees Celsius.
The specific heat of ice at 0 degrees Celsius is approximately 2.09 Joules/gram degree Celsius. This means that it takes 2.09 Joules of energy to raise the temperature of 1 gram of ice by 1 degree Celsius.
I will use this formula. Some conversion will be required. ( I only know specific heat iron in J/gC ) q(Joules) = mass * specific heat * change in temperature Celsius 3 kilograms cast iron = 3000 grams q = (3000 g)(0.46 J/gC)(120 C - 30 C) = 124200 Joules (1 kilojoule/1000 joules) = 124.2 kilojoules of energy needed ===========================
No, heat is a form of energy and is typically measured in joules or calories. Temperature, on the other hand, is measured in degrees Celsius or Fahrenheit and is a measure of the average kinetic energy of particles in a substance.