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How much heat in joules is needed to raise the temperature of 4.0 L of water from 0 degrees Celsius to 70.0 degrees Celsius?
Wiki User
∙ 15y ago
It takes 4.186 Joules to heat one gram of water by 1-degree Celsius.
4.186 * 4000 = 16,744 Joules to heat 4 kilos of water by 1-degree.
16,744 * 70 = 1,172,080 Joules.
The above assumes that one litre of water weighs exactly 1 Kilogram.
Wiki User
∙ 15y ago
The specific heat capacity of water is 4.18 J/g°C. The mass of water is 4000 g. The temperature change is 70.0°C - 0°C = 70.0°C. Therefore, the heat required is 4.18 J/g°C x 4000 g x 70.0°C = 1,170,400 J.
Wiki User
∙ 12y agoConversion needed.
4 kg (1000 grams/1 kg)
= 4000 grams
----------------------now,
q(thermal energy in Joules) = mass * specific heat * change in temperature
q = (4000 grams)(4.180 J/gC)(75 C - 25 C)
= 8.4 X 105 Joules
--------------------------
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Approx 2940 Joules.
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How many calories are needed to raise the temp of 8.1 g of water 20 degrees Celsius?
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How much energy is needed to reduce water temperature from 15 degrees to 14 degrees?
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8.200 J
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How many joules are needed to change the temperature of 1 gram of water by 1C?
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How many joules of energy are needed to heat steam from 100 celsius to 114 celsius?
Approx 2940 Joules.
How many kilojoules of energy are necessary to raise the temperature of 3 kilograms of cast iron from 30 degrees celsius to 120 degrees celsius?
I will use this formula. Some conversion will be required. ( I only know specific heat iron in J/gC ) q(Joules) = mass * specific heat * change in temperature Celsius 3 kilograms cast iron = 3000 grams q = (3000 g)(0.46 J/gC)(120 C - 30 C) = 124200 Joules (1 kilojoule/1000 joules) = 124.2 kilojoules of energy needed ===========================
What is the quantity of heat in joules needed to raise the temperature of 40.0g of Al from 25 degrees Celsius to 50 degrees Celsius?
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Specific heat of air?
The specific heat of air at 0 degrees Celsius is 1.01 Joules per gram or J/g. The specific heat of a substance is defined as the quantity of heat per unit mass needed to raise its temperature by one degree Celsius.
What is the amount of heat needed to raise that temperature of 1 kilogram of water 1 degree Celsius?
The amount of heat needed to raise the temperature of 1 kilogram of water by 1 degree Celsius is 4186 Joules, which is the specific heat capacity of water.
What do you have if your temperature is forty degrees Celsius?
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The specific heat of lead is 128 kg degrees Celsius How much heat is needed to raise the temperature of a kg sample of lead by 10 degrees Celsius?
The relevant equation behind this problem is Q=m*c* ΔT Where Q is the energy that must be added to or taken from the system, m is the mass of the object, c is the objects specific heat, and ΔT is the change in temperature in Celsius or Kelvin. Plugging in the given values we get that Q=.015kg * 128J/(kg*C) * 10C=19.2J. Therefore, you need 19.2 joules of heat in order to raise the temperature of a .015kg sample of lead by 10 degrees Celsius.
How much heat energy is needed to convert 50 kg of water at 80 degrees Celsius to steam at 100 degrees Celsius?
To convert 50 kg of water at 80 degrees Celsius to steam at 100 degrees Celsius, you need to calculate the heat energy needed to raise the temperature of water from 80 to 100 degrees Celsius (specific heat capacity of water) and then the heat energy needed for water to steam phase change (latent heat of vaporization of water). The total heat energy required can be calculated using the formula: Q = mcΔT + mL, where Q is the heat energy, m is the mass, c is the specific heat capacity, ΔT is the temperature change, and L is the latent heat of vaporization.
