8x^3 - 12x^2 + 6x - 9 = (8x^3 - 12x^2) + (6x - 9) = 4x^2(2x - 3) + 3(2x - 3) = (4x^2 + 3)(2x - 3)
6x - 2 = 16 : 6x = 16 + 2 = 18 : x = 18÷ 6 = 3 :x - 3 = 3 - 3 = 0 : x - 3 = 0
6x - 9 = 21 6x = 21 + 9 6x = 28 x = 28/6 Reduce to: x = 14/3
6x + 3 = 2x + 5 4x = 2 x=1/2
3X2 + 6X + 9 3(X2 + 2 + 3) -----------------------3 is a common factor of all terms
From what i understand the equation is like this; (3 * 2 ) + 6x + 24 = 0 6 + 6x +24 = 0 6x = - 24 - 6 6x = - 30 x = - 5
66x^3 - 36x^2 = 6x^2(11x - 6) 55x - 30 = 5(11x - 6) 66x^3 - 36x^2 + 55x - 30 = (6x^2 + 5)(11x - 6)
3-6x = 15 -6x = 15-3 -6x = 12 x = -2
6x + 2 = 6 6x = 4 x = 2/3
If: 6x = 2/3 Then: x = 1/9
9x + 3 - 6x - 2 = 3x + 1
8x^3 - 12x^2 + 6x - 9 = (8x^3 - 12x^2) + (6x - 9) = 4x^2(2x - 3) + 3(2x - 3) = (4x^2 + 3)(2x - 3)
6x - 2 = 16 : 6x = 16 + 2 = 18 : x = 18÷ 6 = 3 :x - 3 = 3 - 3 = 0 : x - 3 = 0
x^2 - 6x - 2 = 0 x^2 - 6x = 2 x^2 - 6x + 9 = 2 + 9 = 11 (x - 3)^2 = 11 x - 3 = +/- sqrt(11) x = 3 +/- sqrt(11)
root (6x - 2) = 4 therefore 6x - 2 = 16 therefore 6x = 16 + 2 therefore x = 3
The slope-intercept form of the equation of a line is y = mx + b, wher m = slope and b = y-intercept.2 - 3y + 6x = 0 just solve for y2 - 2 - 3y + 6x - 6x = 0 - 6x - 2-3y = - 6x - 2-3y/-3 = - 6x/-3 - 2/-3y = 2x + 2/3
x2 + 6x + 1 = 0 x2 + 6x + 9 = 8 (x + 3)2 = 8 x + 3 = ± 2√2 x + 3 = -3 ± 2√2 x ∈ {-3 - 2√2, -3 + 2√2}