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How many different ways can you make 12 cents in change?
I'll use these symbols for each coin: P = Penny; D = Dime; N = Nickel 12 P 7 P & 1 N (7 + 5) 2 P & 2 N (2 + 10) 1 D & 2 P (10 + 2)
A negative x a negative?
A negative times a negative is a positive. A simple way to remember this is... n * p = n p* n = n p * p = p n * n = p There will always be two negatives, and two positives.
If told that 'q' 'p' and 'r' are distinct primes and that there exists 'n' such that 'n equals p x q x r' How many positive factors of 'n' are there and How do you determine what they are?
If p, q and r are distinct primes and n=pxqxr then n will have 8 factors, all of which will be positive since prime numbers are all positive, which are: n(pqr), pq, pr, qr, p, q, r and 1. Here there were 3 distinct primes so the number of positive factors is 2^3. In general if you had p distinct primes then you would have 2^p positive factors.
Need Help With Algebra 2 HW ASAP Suppose you have a 200000 home loan with an annual interest rate of 6.5 percent compounded monthly If you pay 1200 per month what balance remains after 20 years?
The balance is 129178. -------------------- Looking at the amount remaining on the Capital (C) at a rate of r with a repayment of P, there is: After 1 period: Cr - P After 2 periods: (Cr - P)r - P = Cr^2 - Pr - P = Cr^2 - P(r + 1) After 3 periods: ((Cr - P)r - P)r - P = Cr^3 - Pr^2 - Pr - 1 = Cr^3 - P(r^2 + r + 1) After n periods: Cr^n - P(r^(n-1) + r^(n-2) + ... + r + 1) The sum in the brackets that multiplies the repayment P is a geometric progression, which has sum: sum = (r^n - 1) / (r - 1) → the amount remaining after n periods is given by remaining = Cr^n - P (r^n - 1) / (r - 1) With an APR of 6.5%, the yearly rate is 1 + 6.5/100 = 1.065 Compounded monthly, to get the same amount after one year the monthly rate is 1.065^(1/12) ≈ 1.00526 (a monthly percentage rate of approx 0.526%) For 20 years, there are 12 x 20 = 240 monthly periods → amount remaining ≈ 200,000 x (1.00526)^240 - 1,200 x (1.00526^240 - 1) / (1.00526 - 1) ≈ 129,177.88 ≈ 129,178
Q 5th term of a GP is 2 then product of its 9 terms is?
I'll try to answer the question, "If the 5th term of a geometric progression is 2, then the product of its FIRST 9 terms is --?" Given the first term is A and the ratio is r, then the progression starts out... A, Ar, Ar^2, Ar^3, Ar^4, ... So the 5th term is Ar^4, which equals 2. The series continues... Ar^5, Ar^6, Ar^7, Ar^8, ... Ar^8 is the 9th term. The product P of all 9 terms is therefore: P = A * Ar * Ar^2 *...*Ar^8 Collect all the A's P = (A^9)*(1 * r * r^2 ...* r^8) P = A^9 * r^(0+1+2+...+8) There's a formula for the sum of the first n integers (n/2)(n+1), or if you don't know just add it up. 1+2+...+8 = 36 Therefore P = A^9 * r^36 Since 36 is a multiple of 9, you can simplify: P = (Ar^4)^9 Still with me? Remember that Ar^4=2 (a given fact). So finally P = 2^9 = 512. Cute problem.
Is The first P N is 2?
The first Prime Number is 2
If you multiply 2 positive integers will result in what kind of product?
Positive. p*p=p p*n=n n*n=p
What is the formula for solving of induction?
Induction is not a formula, it is a method of proof. Anyway, state the property you wish to prove about each natural number n. This is usually the given P(n). Prove this for the zeroth case, i.e. P(0). Assume the nth case is true, i.e. P(n). Show P(n) => P(n+1). Example: Prove 2 + 4 + ... + 2n = n(n+1) for n >= 0 Proof: P(0) = 0 trivially. Assume: P(n) Show P(n) => P(n+1). 1. 2 + 4 + ... + 2n = n(n+1) 2. 2 + 4 + ... + 2n + 2(n+1) = n(n+1) + 2(n+1) = (n+1)(n+2). QED
A binomial distribution has a mean of 12 and a standard deviation of 2.683 find n and p?
There is not enough information to find n & p. The mean is n*p and the std dev = sqrt (n*p*q). You have to be given n, p or q to have 2 equations 2 unknowns to solve.
How do you use HYPOTHESIS AND TEST STATISTICs?
Means, Proportions and Variance (One population) H_0:μ=μ_0 assuming σ is known z=(x ̅-μ)/(σ⁄√n) N(0,1) NA H_0:μ=μ_0 assuming σ is unknown t=(x ̅-μ)/(s⁄√n) Student t(υ) ν=n-1 H_0:p=p_0 p ̂=x/n or p ̂=(x+2)/(n+4) z=(p ̂-p)/√((p(1-p))/n) N(0,1) NA H_0:σ^2=σ_0^2 u=((n-1) s^2)/σ^2 χ^2 (υ) ν=n-1
How many different ways can you make 12 cents in change?
I'll use these symbols for each coin: P = Penny; D = Dime; N = Nickel 12 P 7 P & 1 N (7 + 5) 2 P & 2 N (2 + 10) 1 D & 2 P (10 + 2)
What does n equal if n plus 2n equals p?
n equals p over 2(like as a division problem. See, you just write n+2n=p then you do this- n+2n=p you take 2 divided by 2 and those cancel ou so if you divide by one so=ide, you have to do it to the other. so you get your answer.
What is the formula for geometric probability?
If you have an experiment in which the probability of success at each trial is p, then the probability that the first success occurs on the nth trial is Pr(N = n) = [(1 - p)^(n-1)]*p for n = 1, 2, 3, ...
What does 2 n in p?
2 Nation in Peace Mean
Formula for Partially ordered set for n elements?
$p(n)\,=\,2^{n^2/4+3n/2+O(\log_2n)}$
How do you multiply negatives?
P= positive N=negative P x N = N N x P = N P x P = P N x N = P Hope that helps!?!?!
How do you get 12.75 with 1 2 3 4?
P(2x3) - 1/4 where P(n) is the n-th prime.
