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Can you prove If m n and p are three consectuive integers then mnp is even?
If m, n, and p are three consecutive integers, then one of them must be even. Let's say the even number is m. Since m is even, it is divisible by two, and so can be written as 2*k, where k is some integer. This means that m*n*p = 2*k*n*p. Since we are multiplying the quantity k*n*p by 2, it must be divisible by two, and therefore must be even.
How do you calculate prime factors?
Let n be the number whose prime factors we so desire to know. Required knowledge: All prime numbers less than sqrt(n).Test n for divisibility by each such prime numbers, starting with 2:If a prime number, p, is found to divide n, divide n by p, record p and continue (test for divisibility by p again) using n/p in the place of n.The recorded prime factors are the prime factors of n.
The variance of first n natural numbers is?
1 Sum of first n natural numbers = n(n+1)2[Formula.]2 Arthmetic mean of first n natural numbers = Sum of the numbers n[Formula.]3 = n(n+1)2n = n+124 So, the Arthmetic mean of first n natural numbers = n+12
How can I how that for any prime number p square root of p is an irrational number?
Suppose not. Let p be prime and n = Sqrt[p]. Since p is an integer, if n is rational, then n is also an integer. So we have n.n = p. But since p is prime, only 1 and p divide p. -><- therefore n must not be rational
If you have a calculate the original number from a percent increase?
Let's set this equation up. Call the original number No and the number you have N and the percentage increase P. The equation to get the number you have ( N ) is No + No x P = N and we want to solve for No so No ( 1 + P ) = N No = N / ( 1 + P )
2 is the first P N?
y. 2 is the first prime no.
If you multiply 2 positive integers will result in what kind of product?
Positive. p*p=p p*n=n n*n=p
What is the formula for solving of induction?
Induction is not a formula, it is a method of proof. Anyway, state the property you wish to prove about each natural number n. This is usually the given P(n). Prove this for the zeroth case, i.e. P(0). Assume the nth case is true, i.e. P(n). Show P(n) => P(n+1). Example: Prove 2 + 4 + ... + 2n = n(n+1) for n >= 0 Proof: P(0) = 0 trivially. Assume: P(n) Show P(n) => P(n+1). 1. 2 + 4 + ... + 2n = n(n+1) 2. 2 + 4 + ... + 2n + 2(n+1) = n(n+1) + 2(n+1) = (n+1)(n+2). QED
A binomial distribution has a mean of 12 and a standard deviation of 2.683 find n and p?
There is not enough information to find n & p. The mean is n*p and the std dev = sqrt (n*p*q). You have to be given n, p or q to have 2 equations 2 unknowns to solve.
How do you use HYPOTHESIS AND TEST STATISTICs?
Means, Proportions and Variance (One population) H_0:μ=μ_0 assuming σ is known z=(x ̅-μ)/(σ⁄√n) N(0,1) NA H_0:μ=μ_0 assuming σ is unknown t=(x ̅-μ)/(s⁄√n) Student t(υ) ν=n-1 H_0:p=p_0 p ̂=x/n or p ̂=(x+2)/(n+4) z=(p ̂-p)/√((p(1-p))/n) N(0,1) NA H_0:σ^2=σ_0^2 u=((n-1) s^2)/σ^2 χ^2 (υ) ν=n-1
How many different ways can you make 12 cents in change?
I'll use these symbols for each coin: P = Penny; D = Dime; N = Nickel 12 P 7 P & 1 N (7 + 5) 2 P & 2 N (2 + 10) 1 D & 2 P (10 + 2)
What does n equal if n plus 2n equals p?
n equals p over 2(like as a division problem. See, you just write n+2n=p then you do this- n+2n=p you take 2 divided by 2 and those cancel ou so if you divide by one so=ide, you have to do it to the other. so you get your answer.
What is the formula for geometric probability?
If you have an experiment in which the probability of success at each trial is p, then the probability that the first success occurs on the nth trial is Pr(N = n) = [(1 - p)^(n-1)]*p for n = 1, 2, 3, ...
What does 2 n in p?
2 Nation in Peace Mean
Formula for Partially ordered set for n elements?
$p(n)\,=\,2^{n^2/4+3n/2+O(\log_2n)}$
How do you get 12.75 with 1 2 3 4?
P(2x3) - 1/4 where P(n) is the n-th prime.
How do you multiply negatives?
P= positive N=negative P x N = N N x P = N P x P = P N x N = P Hope that helps!?!?!
