If you mean: 9x2+3x-2 = (3x+2)(3x-1) when factored
3x^2 - 27 = = 3(x^2 - 9) = 3(x^2 - 3^2) = 3(x - 3)(x + 3)
If that's -9x^3 - 3x^2 + 3x + 1, that factors to (1 - 3x^2)(1 + 3x)
x2 + 3x + 2 factors into (x + 1) (x + 2)
(3x^2 - 4y^2)(3x^2 + 4y^2)
4
3x^2 + x + 2x^2 = 5x^2 + x
do you mean x2 + 3x + 2 ? Factors are (x +2)(x+1)
The factors are [3x + 5 - 2*sqrt(10)] and [3x 5 + 2*sqrt(10)].
(x - 1)(3x + 2)
(3x)^(2-4) = (3x)^-2 = (9x2)^-1 = 1/(9x2)
Factors are (3x + 2)(x + 2) so x is either -2/3 or -2 If term in x is negative then factors are (3x - 2)(x - 2) and solutions are 2/3 and 2.