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Algebra

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A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

The sum or difference of p and q is the of the x-term in the trinomial

A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

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Q: 4x8 plus 5x4 - 2x3 plus x2 - 1?
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What is the coefficient of the term of degree 4 in this polynomial 4x8 plus 5x4-2x3 plus x2-1?

For a single term, the "degree" refers to the power. The coefficient is the number in front of (to the left of) the x.


how do i solve this 5x2 + 3x2 โ€“ x3 + 2x3 + 10x4 โ€“ 5x4?

x2 • (5x2 + x + 8)


X4-2x3 plus 2x2 plus x plus 4 divided by x2 plus x plus 1 solutions?

(x4 - 2x3 + 2x2 + x + 4) / (x2 + x + 1)You can work this out using long division:x2 - 3x + 4___________________________x2 + x + 1 ) x4 - 2x3 + 2x2 + x + 4x4 + x3 + x2-3x3 + x2 + x-3x3 - 3x2 - 3x4x2 + 4x + 44x2 + 4x + 40R∴ x4 - 2x3 + 2x2 + x + 4 = (x2 + x + 1)(x2 - 3x + 4)


2x3 plus 4x2 plus 8x factor the polynomial?

2x(x2+2x+4)


What is the factorization of the trinomial -2x3 plus 2x2 plus 12x?

-2x3 + 2x2 + 12x =(-2x) (x2 - x - 6) =(-2x) (x+2) (x-3)


What is x2 times 2x?

x2 × 2x = 2x3


Quotient and remainder of 3X4 plus 2X3 minus X2 minus x minus 6 divided by X2 plus 1?

(3x4 + 2x3 - x2 - x - 6)/(x2 + 1)= 3x2 + 2x - 4 + (-3x - 2)/(x2 + 1)= 3x2 + 2x - 4 - (3x + 2)/(x2 + 1)where the quotient is 3x2 + 2x - 4 and the remainder is -(3x + 2).


Factor completaly x3 plus 2x3 plus 4xplus 8?

If that's 2x2, the answer is (x + 2)(x2 + 4)


Factor of 2x3 plus 16?

2x3 + 16 = 2(x3 + 8) = 2(x3 + 23) = 2(x + 2)(x2 - 2x + 22) = 2(x + 2)(x2 - 2x + 4)


2x3 plus 2x2 - 12x?

Do you want its factorisation? 2x3 + 2x2 - 12x = 2x(x2 + x - 6) = 2x(x + 3)(x - 2).


What is the factorization of the polynomial below -2x3-2x2 plus 12x?

(-2x3 - 2x2 + 12x) = -2x (x2 + x - 6) = -2x (x + 3) (x - 2)


What is the factorization of this trinomial -2x3 plus 2x2 plus 12x?

-2x3 + 2x2 + 12x = -2x(x2 - x - 6) = -2x(x2 + 2x - 3x - 6) = -2x[ x(x + 2) - 3(x + 2) ] = -2x(x - 3)(x + 2)

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