5+3R = 5R-19bring all the variables to the left side (in this case it will be R)
remember when you bring numbers or variables the sign changes, if the variable or number is positive it shall change to negative and vise versa.
3R-5R= -19-5
-2R = -24
R= -24/-2= 12
checking:
5+3R = 5R-19
so now you substitute R to see if it equation is correct.
5+3(12)= 5(12)-19
5+36=60-19
41=41 SO CORRECT!
(3r + 2)(r - 5)
It is 12r - 20 or 4*(3r - 5)
4r +3 = 3r-2 r + 3=-2 r=-5 basically collect terms so that you get one coefficient of r (in this case 4r on one side and 3r on the other. To get the three r over to the other side you subtract 3r on both sides.) Then r+ 3=-2, so that's simple algebraic manipulation.
1)5r+7=13+2r+3r 2)5r+7=13+5r 3)5r's cancel 7=13 4)Subtract thirteen on both sides 7 =13 -13 -13 5)Answer is no solution because -6 doesn't equal to 0. -6=0 NO SOLUTION!!! Have fun with math!
No. It equals 15.
If: -5 = 7+3r then the value of r works out as -4
(3r + 2)(r - 5)
-5 = 7 + 3r | subtract 7 -12 = 3r | divide by 3 -4 = r
5
-5r + 8r + 5 = 3r +5
-7p + 5r - 6p + 3r = -7p - 6p + 5r + 3r = -(7 + 6)p + (5 + 3)r = -13p + 8r
It is 12r - 20 or 4*(3r - 5)
20r + 10
4r +3 = 3r-2 r + 3=-2 r=-5 basically collect terms so that you get one coefficient of r (in this case 4r on one side and 3r on the other. To get the three r over to the other side you subtract 3r on both sides.) Then r+ 3=-2, so that's simple algebraic manipulation.
5 plus 25 equals 60. Need to solve for 5 plus 25 equals ?: 2 plus 10 equals 24 is equivalent to 2 × (1 plus 5) equals 2 × (12); and 3 plus 15 equals 36 is equivalent to 3 ×(1 plus 5) equals 3 × (12); thus 5 plus 25 equals ? is equivalent to 5 × (1 plus 5) equals 5 × (12); thus ? = 5 × 12 = 60.
Solution:(5r0)2 - (1r1+0r0)*5 + 3r1+1r0 = (8r0)2 - (1r1+0r0)*8 + 3r1+1r0 25 - 5r + 3r + 1 = 64 - 8r + 3r + 13r - 39 = 0r = 13Result: radix r = 13
It equals 24.