5+3R = 5R-19bring all the variables to the left side (in this case it will be R)
remember when you bring numbers or variables the sign changes, if the variable or number is positive it shall change to negative and vise versa.
3R-5R= -19-5
-2R = -24
R= -24/-2= 12
checking:
5+3R = 5R-19
so now you substitute R to see if it equation is correct.
5+3(12)= 5(12)-19
5+36=60-19
41=41 SO CORRECT!
Chat with our AI personalities
(3r + 2)(r - 5)
It is 12r - 20 or 4*(3r - 5)
4r +3 = 3r-2 r + 3=-2 r=-5 basically collect terms so that you get one coefficient of r (in this case 4r on one side and 3r on the other. To get the three r over to the other side you subtract 3r on both sides.) Then r+ 3=-2, so that's simple algebraic manipulation.
No. It equals 15.
1)5r+7=13+2r+3r 2)5r+7=13+5r 3)5r's cancel 7=13 4)Subtract thirteen on both sides 7 =13 -13 -13 5)Answer is no solution because -6 doesn't equal to 0. -6=0 NO SOLUTION!!! Have fun with math!