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7 plus 4xz plus 5 2xz plus 2y?
The direct answer for 7 + 4xz + 5 + 2xz + 2y = 6xz + 2y + 7 For more of an explanation: You have to group the similar things together. You can't add 7 to 4xz just like you can't add 2xz and 2y. So, we'll look through and add each of the like terms together. 7 + 5 = 9. 4xz + 2xz = 6xz. 2y is by itself. So the final solution is 6xz + 2y + 7. We can't simplify the problem and more since we don't know the values for x, y, or z
What are the solutions to the simultaneous equations of 3x plus 2y equals 5 and x plus 2y equals 7?
x = 7 - 2y 3x = 21 - 6y 21 - 6y + 2y = 5 21 - 4y = 5 21 - 16 = 5 4y = 16 y = 4 x + 8 = 7 x = -1 Check it. -3 + 8 = 5 -1 + 8 = 7 It checks.
What are the solutions to the simultaneous equation of 3x plus 2y equals 5x plus 2y equals 14 showing work?
If: 3x+2y = 5x+2y = 14 Then: 3x+2y = 14 and 5x+2y =14 Subtract the 1st equation from the 2nd equation: 2x = 0 Therefore by substitution the solutions are: x = 0 and y = 7
What is the ordered pair for 2x plus 5y equals 16 plus -5x minus 2y equals 2?
2x + 5y = 16 + (-5x) - 2y = 2 That gives 2x + 5y = 2 . . . . . . . . . . (I) and -5x - 2y = - 14 or 5x + 2y = 14 . . . . (II) (I)*5: 10x + 25y = 10 (II)*2: 10x + 4y = 28 Subtracting the second from the first, 21y = -18 so y = -18/21 = -6/7 and then by (I) x = 1 - 5y/2 = 1 - 5/2*(-6/7) = 1 + 15/7 = 22/7 So the ordered pair is (22/7, -6/7)
How do you solve 3x plus 2y equals 7?
You cannot solve one linear equation in two unknown variables.
