zero
20 meters
What is the displacement of a car traveling 10 km north 5km east 15 km south and 5 km north?
The displacement of the hiker can be found by treating the eastward and northward movements as vectors. Using the Pythagorean theorem, the displacement is the square root of the sum of the squares of the distances traveled in each direction. In this case, the displacement is √(3.0 km)^2 + (4.0 km)^2 = √(9 km^2 + 16 km^2) = √25 km^2 = 5.0 km. Therefore, the displacement of the hiker is 5.0 km in a direction that is 53.1 degrees north of east.
2 m south
You divide the distance traveled by the time.
The total displacement is 30 meters South. Displacement is the difference between the initial and final positions of an object, irrespective of the path taken. In this case, the person returns partially to the initial position after moving North by 50 meters.
80
The total displacement of the dog can be calculated using the Pythagorean theorem. After running W meters north and then W meters east, the dog's path forms a right triangle where both legs are W meters. The total displacement is the hypotenuse, which is √(W² + W²) = √(2W²) = W√2. Thus, the total displacement of the dog is W√2 meters in a northeast direction.
fu
"Displacement" in physics usually referrs to the net change in position - meaning, take a snapshot of the dog before he starts moving and a snapshot of the dog when he's finished moving, and the distance between his two positions is his net displacement. Nothing he does in between affects the result - only where he starts and where he ends up.If you walk 6 meters north and then turn around and walk 4 meters south, I hope it makes sense that you are now standing 2 meters north of the point where you started. This is your net displacement (2 meters north).
20 meters
15 meters north. the object is only moving away from the original starting place. its not like its moving away and then back again.
the east /west distances are the same but the north south are different. so subtract the north from the south distances and you end up with 60 meters south.
The answer is 80 because 100-30+10 is 80.
20m
The total displacement of the dog from the starting point can be calculated by finding the net displacement, which is the difference between the distances moved in each direction. In this case, the net displacement would be 6m north - 4m south, resulting in a total displacement of 2m north.
The magnitude of the arrow's displacement would be 53 meters north. Displacement is a vector quantity that represents the distance and direction between the initial and final positions.