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Mike walks 100 meters north then walks 30 meters south After this he walks another 10 meters north What is the magnitude of his total displacement during this walk in meters?
80
What is the total displacement of a dog that runs north 80 meters to chase a ball returns to its mater and then runs south 20 meters?
20m
What is the total displacement of a dog that runs 80 meters to chase a ball returns to its master and the runs south 20 meters?
To find the total displacement, we consider the dog’s initial and final positions. The dog runs 80 meters to chase the ball and then returns 80 meters back to its starting point, resulting in no net displacement from that segment. Finally, when the dog runs 20 meters south, the total displacement is 20 meters to the south. Thus, the total displacement is 20 meters south.
What is the total displacement of a child who walks 4m south 2m north 5m south and 5m north?
To find the total displacement, we need to calculate the net movement in the north-south direction. The child walks 4m south and 5m south, totaling 9m south, and then walks 2m north and 5m north, totaling 7m north. The net displacement is 9m south - 7m north = 2m south. Therefore, the total displacement of the child is 2m south.
If a Displacement vectors of 4 km south 2 km north 5 km north combine to a total displacement of?
To find the total displacement, we can break it down: the 4 km south and the 2 km north result in a net displacement of 2 km south (4 km south - 2 km north = 2 km south). Then, adding the 5 km north gives a total displacement of 3 km north (2 km south + 5 km north = 3 km north). Therefore, the total displacement is 3 km north.
What is the total displacement of a person that travels 80 meters due South than travels another 50 meters due north?
The total displacement is 30 meters South. Displacement is the difference between the initial and final positions of an object, irrespective of the path taken. In this case, the person returns partially to the initial position after moving North by 50 meters.
If you walk 110 meters west then 80 meters north then 110 meters east then 140 meters south what is your displacement?
the east /west distances are the same but the north south are different. so subtract the north from the south distances and you end up with 60 meters south.
Mike walks 100 meters north then walks 30 meters south After this he walks another 10 meters north What is the magnitude of his total displacement during this walk in meters?
80
A boy first walks 120 meters north then turns around and walks 120 meters south his total displacement is?
zero
What is the total displacement of a dog that runs north 80 meters to chase a ball returns to its master and then runs south 20 meters?
20 meters
What is the total displacement of a dog that runs north 80 meters to chase a ball returns to its mater and then runs south 20 meters?
20m
A dog walks 6m north 4m south What is the total displcement of the dog from the starting point?
The total displacement of the dog from the starting point can be calculated by finding the net displacement, which is the difference between the distances moved in each direction. In this case, the net displacement would be 6m north - 4m south, resulting in a total displacement of 2m north.
Mike walks 100 meters north then walks 30 meters south. After this he walks another 10 meters north. What is the magnitude of his total displacement during this walk in meters?
The answer is 80 because 100-30+10 is 80.
What is the total displacement of a dog that runs 80 meters to chase a ball returns to its master and the runs south 20 meters?
To find the total displacement, we consider the dog’s initial and final positions. The dog runs 80 meters to chase the ball and then returns 80 meters back to its starting point, resulting in no net displacement from that segment. Finally, when the dog runs 20 meters south, the total displacement is 20 meters to the south. Thus, the total displacement is 20 meters south.
What is the total displacement of a child who walks 4m south 2m north 5m south and 5m north?
To find the total displacement, we need to calculate the net movement in the north-south direction. The child walks 4m south and 5m south, totaling 9m south, and then walks 2m north and 5m north, totaling 7m north. The net displacement is 9m south - 7m north = 2m south. Therefore, the total displacement of the child is 2m south.
If a Displacement vectors of 4 km south 2 km north 5 km north combine to a total displacement of?
To find the total displacement, we can break it down: the 4 km south and the 2 km north result in a net displacement of 2 km south (4 km south - 2 km north = 2 km south). Then, adding the 5 km north gives a total displacement of 3 km north (2 km south + 5 km north = 3 km north). Therefore, the total displacement is 3 km north.
What is the correct displacement for the following vectors 4 km south km north 5 km south and 5 km north?
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
