Q: What is a person's total displacement when they walk 20 meters North 40 meters East 50 meters South and 20 meters East?

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80

20m

south

Indeed it is.

46 squared + 23 squared = the resultant displacement squared. Pythagoras' theorem.

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The total displacement is 30 meters South. Displacement is the difference between the initial and final positions of an object, irrespective of the path taken. In this case, the person returns partially to the initial position after moving North by 50 meters.

the east /west distances are the same but the north south are different. so subtract the north from the south distances and you end up with 60 meters south.

80

20 meters

zero

20m

The total displacement of the dog from the starting point can be calculated by finding the net displacement, which is the difference between the distances moved in each direction. In this case, the net displacement would be 6m north - 4m south, resulting in a total displacement of 2m north.

The answer is 80 because 100-30+10 is 80.

"Displacement" in physics usually referrs to the net change in position - meaning, take a snapshot of the dog before he starts moving and a snapshot of the dog when he's finished moving, and the distance between his two positions is his net displacement. Nothing he does in between affects the result - only where he starts and where he ends up.If you walk 6 meters north and then turn around and walk 4 meters south, I hope it makes sense that you are now standing 2 meters north of the point where you started. This is your net displacement (2 meters north).

The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.

The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.

south