The rectangle is 15 feet long by 7 feet wide. But let's do the math so you come away with something other than just some numbers for an answer. Length (l) times width (w) will get us the area of a rectangle, as you know. These are the variables in the problem, and they can have different values (hence their being called variables). But we also have one of them expressed in terms of the other one. And we have the area. Let's take that to the "machine" we set up, which is the expression we will create (the "formula" if you prefer) that will lead us to the answer. Roll up your sleeves and let's do this. Arectangle = l x wl = w + 8 [we have l in terms of w, so we can put that back into the original expression] Arectangle = (w + 8) x w [put in the known area (105) and do the multiplication] 105 = w2 + 8w [we used the distributive property of multiplication, as you see, and now we subtract 105 from each side] w2 + 8w - 105 = 0 [yes, we have a second degree equation, but no panic as we'll factor] (w + 15) x (w - 7) = 0 [the two factors, when multiplied, give the original expression] Here's the deal. If we have two numbers that when multiplied together give us a product of zero, then either one of the numbers must be zero, or the othernumber must be zero, or both numbers must be zero. There are two answers for w here, so let's find both of them by setting each number equal to zero and then solving for it. w + 15 = 0 , w = -15 [we subtracted 15 from each side] w - 7 = 0 , w = 7 [we added 7 to each side] We were solving for the width of a rectangle. Can a rectangle have a width with negative length (-15) as solved? No, it can't. But it can have a width of 7 as solved. Let's take the 7 and plug it back into the original expression and solve for l(the length) there. Arectangle = l x w 105 = lx 7 l = 105 / 7 = 15 [105 divided by 7, which is the width, gives us the length] The length of the rectangle is 15 feet as discovered. The 7 x 15 = 105, and 7 + 8 = 15, so we've checked it and found it to be good. Piece of cake.
I can give the width of one of the rectangles. The first rectangle of area 15 cm2 and length of 5 cm has width of 3 cm. It is impossible to know the width of the other rectangle of area 60 cm2. However, if you had said that the two rectangles were similar, then the dimensions of the second rectangle would be 10 cm X 6 cm. But you didn't say that the two rectangles were similar; so there are infinite possibilities of what the dimensions of the second rectangle might be.
If you are trying to find the ratio of the lengths of two similar rectangles, divide the length of one side of one rectangle by the corresponding side length of the other rectangle. To find the ratio between their volumes, divide the volume of one rectangle by the volume the other rectangle. To find volume, multiply the width of the rectangle by the length of the rectangle.
All squares are rectangles, but not all rectangles are squares. Basically, a square is a rectangle where all sides are the same length. However, providing that the width is half of the length, or vice versa, and you join the two rectangles along the one of the sides that is longer, two rectangles can make a square. Example: 1x2 rectangle joined with another 1x2 rectangle will make a 2x2 square.
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
Letting x be the length of the rectangle and (x - 8) be the width of the rectangle,x(x - 8) = 153,subtracting 153 from each side, x2 - 8x - 153 = 0,solving for x, (x - 17)(x + 9) = 0, then x = 17 or x = -9,substituting 17 for x, the dimensions of the rectangle are 17cm and 9cm.
Rectangles have two dimensions: length and width. Multiply them together and you will get the area in square units.
I can give the width of one of the rectangles. The first rectangle of area 15 cm2 and length of 5 cm has width of 3 cm. It is impossible to know the width of the other rectangle of area 60 cm2. However, if you had said that the two rectangles were similar, then the dimensions of the second rectangle would be 10 cm X 6 cm. But you didn't say that the two rectangles were similar; so there are infinite possibilities of what the dimensions of the second rectangle might be.
Area = 35*35 = 1225 square m With the dimensions given it is not a rectangle but it is a square <><><><> Above is correct- but squares are also rectangles.
96 units squared. To find area of rectangles, simply multiply the two dimensions (length and width) which in this case are 12 and 8.
It has 2 dimensions which are length and width
No rectangle can have equal perimeter and length.
They are also known as the "dimensions" of a rectangle.
You can't tell the dimensions from the perimeter. There are an infinite number of different rectangles, all with different lengths and widths, that all have the same perimeter.
A rectangle with a length of 10 and a width of 24
No. The square is a special case of rectangle where all the sides are of equal length. So some rectangles are squares, and all squares are rectangles.
If you are given two similar rectangles, one with all measurements and the other with only one, you first need to find the conversion ratio. Let's call the rectangle that you know everything about, rectangle A, and the other rectangle B. You take the ratio of the side of rectangle B to rectangle A. You then multiply the length of rectangle A by this value, to find the length of rectangle B.
If you are trying to find the ratio of the lengths of two similar rectangles, divide the length of one side of one rectangle by the corresponding side length of the other rectangle. To find the ratio between their volumes, divide the volume of one rectangle by the volume the other rectangle. To find volume, multiply the width of the rectangle by the length of the rectangle.