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Let the numbers be 'm' & 'n' m + n = 34 4m + 4 = n (4 times smaller is 4 less than the larger). Algebraically rearrange m + n = 34 4m - n = -4 Add 5m = 30 m = 6 Hence n = 28 (4 x 6 + 4 = 28). So the two numbers are 6 & 28 .
To move to a larger measure, divide by s-cubed where s is the scale factor between the smaller linear measure and the bigger one. For example, To convert from cm3 to metre3 , 1 cm = 0.01 m so n cm2 = n*(0.01)3 cubic metres.
Let the integers be n and n + 1.n + 3(n+ 1) = 47 4n + 3 = 47 4n = 44 n = 11 n+ 1 = 12.
Well, darling, that would be an egg. It's larger than a man when it comes to weight, but smaller than a hen in terms of size. So, there you have it - an egg, the perfect in-between size for all your poultry needs.
Let the smaller number be n then the larger number is n + 2. n(n + 2) = 2115 n2 + 2n - 2115 = 0 This equation factorises (n + 47)(n - 45) = 0 The only relevant solution is when n is a positive number. When n - 45 = 0 then n = 45. The two consecutive odd numbers are therefore 45 and 47