a motive
To move to a larger measure, divide by s-cubed where s is the scale factor between the smaller linear measure and the bigger one. For example, To convert from cm3 to metre3 , 1 cm = 0.01 m so n cm2 = n*(0.01)3 cubic metres.
Let the integers be n and n + 1.n + 3(n+ 1) = 47 4n + 3 = 47 4n = 44 n = 11 n+ 1 = 12.
Let the smaller number be n then the larger number is n + 2. n(n + 2) = 2115 n2 + 2n - 2115 = 0 This equation factorises (n + 47)(n - 45) = 0 The only relevant solution is when n is a positive number. When n - 45 = 0 then n = 45. The two consecutive odd numbers are therefore 45 and 47
33,250.
Let the two odd numbers be n and n+2, then : 2(n + 2) + 13 = 3n 2n + 4 + 13 = 3n n = 17 The smaller of the two odd numbers is 17 and the larger number is 19.
a motive
a motive
Let the smaller be n, then the larger is n+1; and: n + 4(n+1) = 59 → n + 4n + 4 = 59 → 5n = 55 → n = 11 → the two consecutive integers are 11 and 12.
Suppose n is the smaller integer. Then the larger integer is n + 1, so that 5 times the larger is 5*(n + 1). Their sum is n + 5*(n + 1) = 6n + 5 Therefore 6n + 5 = 41 6n = 41 - 5 = 36 So that n = 36/6 = 6
A smaller version of a larger map.
Dna is a part of the cell.
theme of keeper 'n me
let the smaller number be n; then the larger number is 2n, and their sum is n + 2n = 3n = 1407 → dividing 1407 by 3 will give the smaller number: n = 1407 ÷ 3 = 469 → multiplying this by 2 gives the larger number: 2n = 2 x 469 = 938
To move to a larger measure, divide by s-cubed where s is the scale factor between the smaller linear measure and the bigger one. For example, To convert from cm3 to metre3 , 1 cm = 0.01 m so n cm2 = n*(0.01)3 cubic metres.
universal theme ...Apex:)
Let the integers be n and n + 1.n + 3(n+ 1) = 47 4n + 3 = 47 4n = 44 n = 11 n+ 1 = 12.
a perfect square is any integer times it self for example:3 x 3= 9, so 9 is a perfect squareIf you do not have a calculator with 'square root' function or an xy key then you will have to do it by the process of guessing and elimination.To find if a number (N) is a perfect square:Divide the (N) by a number (D) that is reasonabe.If the result is larger than (N) then try a larger (D).If the result of N/D is smaller than (D), choose a smaller (D).Continue until you have narrowed (D) down to an integer that is the square root of (N) or come to the conclusion that (N) is not a perfect square - (D-1)2 is smaller than (N) and D2) is largerTo find if a number (N) is a perfect cube:Do as above but divide the result of N/D by D again - Do N/D2 and compare that result to D