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The given sequence is an arithmetic progression.

a = first term of A.P. = 10, d = common difference = an - an-1 = -4

nth term of an A.P. is given by: an = a+(n-1)d

Plugging in the values we get an = 10+(n-1)(-4) = 10 - 4n + 4 = 14 - 4n.

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