The given sequence is an arithmetic progression.
a = first term of A.P. = 10, d = common difference = an - an-1 = -4
nth term of an A.P. is given by: an = a+(n-1)d
Plugging in the values we get an = 10+(n-1)(-4) = 10 - 4n + 4 = 14 - 4n.
It is: nth term = -4n+14
The nth term is (2n - 12).
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
10 - 4n
Ah, what a lovely sequence you have there! To find the nth term, you notice that each number is increasing by 2. So, if we start at 6, the nth term can be represented by the formula 2n + 4. Happy calculating, my friend!
It is: nth term = -4n+14
The nth term is (2n - 12).
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
10 - 4n
The sequence 4, 6, 8, 10 is an arithmetic sequence where each term increases by 2. The nth term formula can be expressed as ( a_n = 4 + (n - 1) \cdot 2 ). Simplifying this gives ( a_n = 2n + 2 ). Thus, the nth term of the sequence is ( 2n + 2 ).
By varying the parameters of a quartic polynomial, the nth term can be made whatever you like. But, taking the simplest solution, Un = 2 - 4n for
To find the nth term of the sequence 4, 10, 18, 28, 40, we first identify the pattern in the differences between consecutive terms: 6, 8, 10, and 12. The second differences are constant at 2, indicating a quadratic sequence. The nth term can be expressed as ( a_n = n^2 + n + 2 ). Thus, the nth term of the sequence is ( n^2 + n + 2 ).
Ah, what a lovely sequence you have there! To find the nth term, you notice that each number is increasing by 2. So, if we start at 6, the nth term can be represented by the formula 2n + 4. Happy calculating, my friend!
Un = 2n + 2 is one possible answer.
The sequence 8, 6, 4, 2, 0 is an arithmetic sequence with a common difference of -2. The first term (a) is 8, and the common difference (d) is -2. The nth term can be expressed using the formula: ( T_n = a + (n-1)d ). Thus, the nth term is given by ( T_n = 8 + (n-1)(-2) = 10 - 2n ).
The nth term of the sequence is (n + 1)2 + 2.
The nth term is 9n-2