3x2 + 4x factors to x(3x + 4)
(3x4 + 2x3 - x2 - x - 6)/(x2 + 1)= 3x2 + 2x - 4 + (-3x - 2)/(x2 + 1)= 3x2 + 2x - 4 - (3x + 2)/(x2 + 1)where the quotient is 3x2 + 2x - 4 and the remainder is -(3x + 2).
(3x + 4)(2x - 1) = 0 3x = -4 x = -4/3 2x = 1 x = 1/2 x = 1/2, -4/3
6x-6x=0 so all you have left is -16 and there is nothing to factor. I am guessing you meant 6x2 -6x-16 which is 2(3x2 -2x-8) The factor pairs for 8 are 1,8 and 2,4. So let's try 1, 8. We know one of them has to be negative. We see it does not work and when we try 2 and 4 they do not work also. So we cannot factor (3x2 -2x-8) over the integers and we call it prime. The final answer is 2(3x2 -2x-8)
3x4,1x12 and 6x2
2(3x2 - 2)
6x2 - 4x (6/2)x2 - (4/2)x = 3x2 - 2x ========
(3x+1)(2x+4) = 6x2+4+2x+12x = 6x2+14x+4
6x2 - 4x (6/2)x2 - (4/2)x = 3x2 - 2x ========
Dividing all terms by 4 gives: x2-6x+8 = (x-2)(x-4) when factored
If it is 3x2 + 4 = 2x + 4, then you can subtract 4 from both sides, and get 3x2 = 2x, and then x = 2/3
3x2-7x+4 = (3x-4)(x-1) when factored
The expression may be : 6x2 + 17x + 12 This factors as, 6x2 + 17x + 12 = (3x + 4)(2x + 3) Or, the expression could be : 6x2 - 17x + 12 This factors as, 6x2 - 17x + 12 = (3x - 4)(2x - 3)
(3x + 4)(2x - 1)
16? using 16, you have (3x2 + 4)(3x2 + 4) = 9x2 + 24x + 16
2(3x^2 + 6x + 2)
6x2+23x+20=0x= .7275 and -4.5634Improved Answer:-6x2+23x+20 = (3x+4)(2x+5) when factored