Yes; less than one pixel is 0 pixels which is nothing = no image
Vector images can be of any size but when rendered to screen (or any imaging device which uses pixels) of course the result must be at least 1 pixel for the object to appear. The vector object might very well be there but be invisible due to the (low) resolution of the imaging output.
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The length of the third side must be greater than the difference between the length of the two given sides and it must be less than the sum of the two given sides. These limits can be derived from the fact that any two sides of a triangle must have a combined length greater than the third side.
> No. One side must be greater than the sum of the other two. Actually, each side must be shorter than the sum of the other two in order to build a triangle. In this case, the side of length 16 is not shorter than the sum of the other two sides.
The triangle with side lengths of 2m, 4m, and 7m does not form a valid triangle. In a triangle, the sum of the lengths of any two sides must be greater than the length of the third side according to the Triangle Inequality Theorem. In this case, 2m + 4m is less than 7m, violating the theorem. Therefore, a triangle with these side lengths cannot exist in Euclidean geometry.
This is like solving the folloging inequality (for the unknown numerator): x/5 > 3 Multiplying both side by five gives you: x > 15 So the numerator must be greater than 15.
Oh, what a happy little question! It looks like you have a special triangle there with side lengths 30, 32, and 34. Since the sum of the two shorter sides must be greater than the longest side for a triangle to exist, let's check if that's true here. If we add 30 and 32, we get 62, which is indeed greater than 34, so you can paint a beautiful triangle with those side lengths!