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If the discriminant of a quadratic equation equals zero what is true of the equation?
It has one real solution.
Why do quadratic equations where the discriminant is 0 have exactly 1 real solution?
Suppose the quadratic equation is ax^2 + bx + c = 0 and D = b^2 - 4ac is the discriminant. Then the solutions to the quadratic equation are [-b ± sqrt(d)]/(2a). Since D = 0, the both solutions are equal to -b/(2a), a single real solution.
How do you solve imaginary equations?
The answer depends on the nature of the equation. Just as there are different ways of solving a linear equation with a real solution and a quadratic equation with real solutions, and other kinds of equations, there are different methods for solving different kinds of imaginary equations.
How many real solution exist for the equation 1.1x2 plus 3.3x plus 4 equals 6?
1.1x2 + 3.3x + 4 = 6 First rearrange the equation to equal zero so that we can use the quadratic formula. 1.1x2 + 3.3x - 2 = 0 Using the quadratic formula, the solutions are x = -3.52 and x = 0.52 Both of these solutions are real, so the original equation has two real solutions.
Real life application of quadratic equation?
How about the path a baseball takes when hit by a bat...
