Best Answer

Assuming a 3x3 square, yes.

If you want to know a solution where all rows, columns and diagonals sum to 15, it is:

2 9 4

7 5 3

6 1 8

More answers

Assuming you're referring to a 'magic square' one solution would be...

816

357

492

Q: Can sums all rows equal 15 using 1 -9 only once?

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2 7 6 9 5 1 4 3 8

20

63

Of course. You have a choice of several different lovely arrangements:18 rows with 1 in each row9 rows with 2 in each row6 rows with 3 in each row

18 Chairs into equal rows - 6 x 3 2 x 9 18 x 1

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No.

No.

If you are thinking of a mgic square, the answer is NO. The nine numbers sum to 45 so if you have three rows with equal sums, that sum can only be 45/3 = 15. You can have two rows, each adding to 17, and using the digits only once, but you will not use all digits.

2 7 6 9 5 1 4 3 8

No. The sum of 1-9 is 45 and 12 does not divide 45.

10

There are 9 numbers. Assuming the question refers to a 3x3 "magic" square, the answer is no. The sum of all nine numbers is 36 so each of the 3 rows must sum to 12.

20

2 rows of 18 squares3 rows of 12 squares4 rows of 9 squares6 rows of 6 squares9 rows of 4 squares12 rows of 3 squares18 rows of 2 squares36 rows of 1 squareI would not count "1 row of 36 squares", because you only have a single row that cannot equal another row (there is only one rowafter all). If this is for homework, I would state your reasoning for excluding (or including) that set. Count all the options up, and you have 8 different ways you can arrange the rows with the exclusion.

If the version of Excel you are using only has 65536 rows, which was the case up to Excel 2003, then you can't add any more rows. From Excel 2007 onwards there are 1048576 rows, so that is what you would need to use.

No.

This is a square matrix where the number of rows and the number of columns are equal.